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Kazeer [188]
3 years ago
6

Geometry:( *image shown above*

Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:

y=-3.5x-9.5

Step-by-step explanation:

Alborosie3 years ago
8 0

Answer:

Step-by-step explanation:

so we use the equation y2-y1=m(x2-x1)

let's say (-3,1) is point 1 and (-5,8) is point 2

we plug in what we know

8-1=m(-5-(-3))

subtracting a negative is the same as adding so -5 - (-3) = -2

7=-2m

divide both sides by -2

-7/2=m

-3.5=m

so slope intercept form is y=mx+b

we know the slope (m) but we still need the "b" which is the y-intercept.

so you pick whichever point you want (I'm going to chose point 1 but it doesn't matter) and plug it in

1=-3.5(-3)+b

1=10.5+b

-9.5=b

so the equation would be y=-3.5x-9.5

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Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4
Vladimir79 [104]

Answer:

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3) ⇒ 2nd

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Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

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∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

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∴ The expression 32y^{10}-24 = 8(y^{10}-3) is completely factored

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∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of y^{7} and y² is y²

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- Divide each term by 10y² to find the terms in the bracket

∴ 20y^{7}+10y^{2}=10y^{2}(2y^{5}+1) ⇒ not the same with the answer

∵ The expression is 16y^{5}+12y^{3}

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of y^{5} and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ the same with the answer

∴ The expression 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) is completely factored

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3)

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)

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