Answer: Infinitely Many Solutions
Step-by-step explanation is below.
I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
Answer:
w = 6.7451
x = 8.0805
Step-by-step explanation:
Find W
Tan(56) = opposite / adjacent
opposite = 10
Adjacent = w
Tan (56) = 10/w
w*Tan(56) = 10
w = 10 / tan(56)
w = 10/ 1.4826
w = 6.7451
Find x
Tan (34) = 10 / (w + x)
Tan (34) = 0.6745
(w + x) * Tan(34) = 10
w + x = 10 / tan(34)
w+ x = 10 / 0.6745
w + x = 14.826
But we found w = 6.7451
6.7451 + x = 14.826
x = 14l826 - 6.7451
x = 8.0805
Given:
The equation is
To find:
The solution of the given equation.
Solution:
We have,
It can be written as
Multiply both sides by 7.
Divide both sides by 7.
Therefore, the value of z is -2.
