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2 years ago

AABC = AGHL Complete the congruence statement AB =

Mathematics

1 answer:

sweet [91]2 years ago

4 0

Answer:

AB = AH

Step-by-step explanation:

Hope This Helps!!

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The rational number that expresses a loss of $25.30 is +$25.30 -$25.30 +$2.53 -$2.53 , and the rational number that represents a

Mkey [24]

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Natali [406]

Answer:

I'm in 10th grade so I'll see what I can do and will answer to the best of my ability.

Step-by-step explanation:

What Julie did wrong was, she did simplify she just did it wrong. She used 4*8 which does equal 32 but 8 can't be simplified anymore than that. If she would of used 2*16 then her answer would be right.

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Answer:

2! Thank it if it was helpful :D

Step-by-step explanation:

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2 years ago

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Train a is traveling at 30 mph faster than train b. If train a travels 350 miles in the same amount of time that train b travels

GalinKa [24]

Answer:

20 mph

Step-by-step explanation:

Let speed of Train a = Va mph

Let speed of Train b = Vb mph

Va = Vb + 30

Let time taken for Train a = Ta

Let time taken for Train b = Tb

time taken = distance travelled/speed

Ta = 350/Va = 350/(Vb+30)

Tb = 140/Vb

But they both travel in the same amount of time.

So, Ta = Tb

$\frac{350}{v_{b} + 30}=\frac{140}{v_{b}}$

Cross multiply

$350v_{b} = 140(v_{b} + 30)\\\\350v_{b} = 140v_{b} + 4200\\\\350v_{b} -140v_{b} = 4200\\\\210v_{b} = 4200$

Divide both sides by 210

$\frac{210v_{b} }{210} \frac{4200}{210} \\\\v_{b} = 20 mph$

4 0

2 years ago

PLEASE HELP ME!!!!!!!!!

vitfil [10]

$(x - 4) {}^{2} - 28 = 8 \\ (x - 4) {}^{2} = 8 + 28 \\ (x - 4) {}^{2} = 36$

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

$\sqrt{(x - 4) {}^{2} } = ± \sqrt{36} \\x - 4 = ±6 \\ x _{1}- 4 = 6 \: \: \: \: \: \: \: \: \: \: x _{2}- 4 = - 6 \\ x_{1} = 6 + 4 \: \: \: \: \: \: \: \: \: \: x_{2} = - 6 + 4 \\ x_{1} = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 2$

Well he started off correct to the point of completing the square.

$(x - 3) {}^{2} = 16 \\ x - 3 = ±4 \\ \: x_{1} - 3 = 4 \: \: \: \: \: \: \: \: \: \: \: \: x_{2} - 3 = - 4 \\ x_{1} = 7 \: \: \: \: \: \: \: \: \: \: x_{2} = - 1$

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4 months ago

AABC = AGHL Complete the congruence statement AB = ​

AABC = AGHL Complete the congruence statement AB =