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iragen [17]
3 years ago
12

Given that l is parallel to line m, find x a. 1 b. 25 c. 3 d. 35

Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
I WOULD SAY IT IS B>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
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Dafna11 [192]

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nice for you                                                                                                                                   / fyi this is payback

5 0
3 years ago
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Please help! Need answer to number 4
alekssr [168]

Answer: H, 1/21

Step-by-step explanation:

7 letters in October

1 b / 7 letters

2 o / 6 letters

1/7 * 2/6 = 2/42 = 1 / 21

5 0
3 years ago
A class survey in a large class for first-year college students asked, “About how many minutes do you study on a typical weeknig
Anika [276]

Answer:  (110.22, 125.78)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

\mu\ \pm z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Sample size = 463

\mu=118\text{ minutes}

\sigma=65\text{ minutes}

Significance level : \alpha=1-0.99=0.01

Critical value : z_{\alpha/2}=z_{0.005}=\pm2.576

We assume that the population is normally distributed.

Now, the 90% confidence interval for the population mean will be :-

118\ \pm\ 2.576\times\dfrac{65}{\sqrt{463}} \\\\\approx118\pm7.78=(118-7.78\ ,\ 118+7.78)=(110.22,\ 125.78)

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)

3 0
3 years ago
Solve: what is 32% of 60?
Viktor [21]
32% of 60
32% × 60
0.32 × 60
19.2
4 0
3 years ago
Read 2 more answers
7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and
Juliette [100K]

Answer:

A) JK and AB =

[tex] \boxed{( \theta) = \f{12}{( \theta)} } So, =》 \dfrac{10}{5} = \dfrac{1}{ \( \theta) } =》 \( \theta) = \dfrac{5}{2}[/tex]

B) AABC

[tex] \boxed{( \theta) = {1}{( \theta)} } So, 23}{-18=\\Ans } \boxed

C) AABM:

[tex] e \fbox{: } The value of k for which \sin(jm) = \cos(x) is \dfrac{\p}{2} ans[/tex]

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3 0
3 years ago
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