13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
<u>Step-by-step explanation:</u>
Total mass of acid required= 85 ounces
Let the mass of 72% acid be 'a'
Let the mass of 25% acid be 'b'
a + b = 85
b = 85-a
85(40/100) = a(72/100) + b(25/100)
85(2/5) = a(72/100) +(85- a) (25/100)
34 = (72a/100) + (2125/100) - (25a/100)
34 - (2125/100) = (72a + 25a) /100
(3400-2125)/100 = 97a /100
97a = 1275
a = 13.15 ounces
b = 85 - 13.14
b = 71.85 ounces
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
<span>You have to calculate two separate measures, one for each set.The mean-to-MAD ratio is the mean divided by the MAD, i. e. mean / MAD. For the set 1, mean = 10.7 and MAD = 2.4, then mean / MAD = 10.7 / 2.4 = 4.4583. For the set 2, mean = 13.7 and MAD is 2.5, so mean/ MAD = 13.7 / 2.5 = 5.480.</span>
Answer:
oh its very simple
Even E²=t²×x²
formula
now please mark me as brainliest
Answer:
Yes
Step-by-step explanation:
There both equal, have the same amount of angle degrees.
