All categories

3 years ago

What is the means-to-MAD ratio of the two data sets, expressed as a decimal?

1 answer:

3 0

You have to calculate two separate measures, one for each set.The mean-to-MAD ratio is the mean divided by the MAD, i. e. mean / MAD. For the set 1, mean = 10.7 and MAD = 2.4, then mean / MAD = 10.7 / 2.4 = 4.4583. For the set 2, mean = 13.7 and MAD is 2.5, so mean/ MAD = 13.7 / 2.5 = 5.480.

You might be interested in

The value of expression x 2 + 3x 2 − 5n − 2 when x = 2 is

Mumz [18]

2 + 3x

= 5

Have a Nice day

3 0

2 years ago

Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on

boyakko [2]

Answer:

Mathew invested $600 and $2400 in each account.

Solution:

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest $(I_1)$ earned in first account for one year,

$\text {simple interest}=\frac{\text {pnr}}{100}$

Where

p = amount invested in first account

n = number of years

r = rate of interest

hence, by using above equation we get $(I_1)$ as,

$I_{1}=\frac{P \times 1 \times 3}{100}$ ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest $(I_2)$ earned in second account,

$I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2$

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

$I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3$

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

$I = I_1+ I_2 ---- eqn 4$

By substituting eqn 1 , 2, 3 in eqn 4

$\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}$

$\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}$

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600

Hence, Mathew invested $600 and $2400 in each account.

3 0

3 years ago

Read 2 more answers

PLEASE HELP! A campground rents bicycles by the hour. The total cost y to rent a bicycle, including deposit, is presented by the

Lelu [443]

The domain and the range of the function are all possible values of the x and y, respectively, that function can take.
The range is given by:

$y_{o}= \frac{3}{3} +12 \\ y_{o}=12 \\ \\ y_{e}= \frac{27}{3} +12 \\ y_{e}=21 \\ \\ \boxed {Im=(y\in R \mid 12\leq y \leq 21)}$

The domain is given by:

$\boxed {D=(x\in R \mid 3\leq y \leq 27)}$

4 0

2 years ago

I will pick brainliest first come, first serve! I need help! Give me an answer that makes sense!

nordsb [41]

Step-by-step explanation:

Total amount of apples in one bag:

$x + y + z$

Hence, total amount of apples in two bags:

$2(x + y + z)$

$2x + 2y + 2z$

$x + x + y + y + z + z$

Hence, B, D and E are correct.

A is incorrect because you are adding 2 more apples on top of the total amount of apples in one bag, and you cannot assume that there are 2 apples in each bag.

C is incorrect because you are multiplying the apples together, but you are supposed to add them up to find the total.

F is incorrect because you are finding 1/2 a bag.

3 0

3 years ago

if one store is selling 3/4 of a bushel of apples for 9 dollars and another store is selling 2/3 of a bushel of a apple for 9 do

fredd [130]

3/4 of a bushel is 75%, 2/3 of a bushel is 66.67% about. Being that both cost $9 the first store who is selling 3/4 of a bushel is a better deal because you get more for what you pay for.

8 0

2 years ago