Answer:
one-sixth of 138
Step-by-step explanation:
36÷3=12. 138÷6=23
12<23
Therefore, one-sixth of 138 is greater than a third of 36.
This expression can't be solved because we don't know the value of e. Basically what this means is that e, an unknown number, is first being multiplied by 9, and it is then added by 10. You will just leave it as it is.
Let g the inverse function of f.
The most important property of g and f being inverses of each other, is that
g(f(x))=x, also f(g(x))=x
so, what one function 'does' to x, the other 'undoes' it.
Thus, we have:
f(g(x))=x and alos f(g(x))= -g(x)+3, from the rule
thus :
-g(x)+3=x
-g(x)=x-3
g(x)=-x+3
check: f(g(x))=f(-x+3)=-(-x+3)+3=x-3+3=x
Answer: the inverse of f is g, such that g(x)=-x+3
So, XZ= 7x+1 and PZ= 4x-1. To figure out XP we have to subtract those two.
(7x+1)-(4x-1)
3x-2
3(8)-2
24-2
22
XP=22
