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3 years ago

Can someone please HELP MEEE!!!!

Mathematics

2 answers:

Volgvan3 years ago

6 0

Answer:

176°F ..........................

sergejj [24]3 years ago

4 0

Answer:

Hey buddy, here is your answer. Hope it helps you.

Step-by-step explanation:

9/5*80+32

=9*16+32

=144+32

=176 degrees F

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Question 4

den301095 [7]

Answer:

40.2

Step-by-step explanation:

Diameter = 16, Radius = 16/2 = 8

Central angle = 2π/5 radians = 72°

Sector area,

8²π×(72/360)

= 64π/5

= 40.2 (rounded to the nearest tenth)

Answered by GAUTHMATH

6 0

3 years ago

Help ASAP! I’m confused. Thanks!!

KATRIN_1 [288]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Comporueba si las siguientes fracciones son equivalentes.

NikAS [45]

Answer:

No sé si este es un problema de opción múltiple, pero tanto (A) como (B) son fracciones equivalentes.

Step-by-step explanation:

4 0

3 years ago

45°

ioda

Answer:

$x = \sqrt{\frac{7}{2} }$

Step-by-step explanation:

<u><em>Explanation</em></u>

From given graph

AC = √7

Given angle ∝ = 45°

$cos\alpha = \frac{adjacentside}{Opposite side}$

$cos45 = \frac{x}{\sqrt{7} }$

$\frac{1}{\sqrt{2} } = \frac{x}{\sqrt{7} }$

$x = \frac{\sqrt{7} }{\sqrt{2} }$

$x = \sqrt{\frac{7}{2} }$

x = 1.8708

7 0

3 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago