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stiks02 [169]
3 years ago
6

Which moving object has a greater unit rate? Explain how you know.

Mathematics
1 answer:
Nikitich [7]3 years ago
8 0

Answer: A

Step-by-step explanation: A, because it by the end of all of this, (A) manages to reach to the top, and B stretches across the chart/ which is considered the distance. Also if you look where the points are, you can see that point A rose quicker in shorter time.

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College algebra ! Help ASAP !!!
Yanka [14]

Answer:

{1}

Step-by-step explanation:

We find determinant for the given matrix and set it equal to -1

To find determinant we apply formula

|A| = a_{11}(a_{22}a_{33} − a_{32}a_{23}) - a_{12}(a_{21}a_{33} − a_{31}a_{23})+a_{13}(a_{21}a_{32} - a_{31}a_{22})

|A| = x(1x - 2) - 0(7-7) + 0(14-7x)

|A| = x^2 - 2x

Now we set the determinant = -1

x^2 - 2x=-1

Add 1 on both sides

x^2 - 2x + 1=0

Now factor it

(x-1)(x-1) = 0

Set each factor =0  and solve for x

x- 1=0 so x=1



8 0
3 years ago
Write LCM of 35 and 144 (If you are not able to send a picture, then you can write step wise, please do not write a direct answe
Alex_Xolod [135]

Answer:

<h2>5040</h2>

Step-by-step explanation:

<h3>multiply 35 by 144 which will give you your answer (lcm)</h3>
3 0
3 years ago
I NEED HELP PLEASE ASAP !
In-s [12.5K]

The first rule you need to know is

(a^b)^c=a^{bc}

So, you have

\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{25\cdot(-6)}}{x^{-3\cdot 48}}=\dfrac{x^{-150}}{x^{-144}}

The second rule you need to know is

\dfrac{a^b}{a^c}=a^{b-c}

So, you have

\dfrac{x^{-150}}{x^{-144}}=x^{-150-(-144)}=x^{-150+144}=x^{-6}

4 0
4 years ago
Read 2 more answers
Line AB contains points A(3,-2) and B(1,8). the slope of line AB is?
ipn [44]
The slope of a line is \frac{y_2 - y_1}{x_2 - x_1}. We have the points (3, -2) and (1, 8). Let's substitute those into the formula. 
\frac{8 - (-2)}{1-3}
subtracting a negative is the same as adding, so that makes our equation
\frac{8+2}{1-3}
\frac{10}{-2}
slope = -5
4 0
4 years ago
The graph of f(x) = |x| is transformed to g(x) = [X + 11-7. On which interval is the function decreasing?
puteri [66]

Answer:

The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

Step-by-step explanation:

* Lets explain how to solve it

- Decreasing function means a function with a graph that moves

 downward as it is followed from left to right.

- For example, any line with a negative slope is decreasing function

- Lets look to the attached graph to understand the meaning of the

 decreasing function

∵ f(x) = IxI ⇒ green graph

∵ g(x) = Ix + 1I - 7 ⇒ purple graph

- From the graph f(x) translated 1 unit to the left and 7 units down to

 form g(x)

- The domains of f(x) and g(x) are all real numbers {x : x ∈ R}

- The range of f(x) is {y : y ≥ 0}

- The range of g(x) is {y : y ≥ -7}

# For f(x)

- The slope of the green line from (-∞ , 0) is negative

- The slope of the green line from (0 , ∞) is positive

# For g(x)

- The slope of the purple line from (-∞ , -1) is negative

- The slope of the purple line from (-1 , ∞) is positive

∵ The line with negative slope represent decreasing function

∴ The interval of the decreasing function is (-∞ , -1) ⇒ g(x)

∴ The interval of the decreasing function is (-∞ , 0) ⇒ f(x)

7 0
4 years ago
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