30 min = 30/60 hr = 0.5 hr
d = rt
100 = r*0.5
100/0.5 = r
200 = r
r = 200 mph.
We know that Rate = distance/time
(30 minutes is .5 hour)
Rate=100 mile/.5 hour
Divide and we get:
Rate=200 MPH
(Hint: MPH is Miles per Hour---Per means "for each")
Make sense?
Answer:
C
Explanation:
You could solve this in the elimination way that I have been done in here.
I use Jason as an example that he paid $11.84 for 5t ( tacos ) + 1q ( quesadilla )
Therefore we could do the elimination if the taco cost 3.45 x 5 = 17.25, would be over the cost.
-> Cross B answer
Then we take 1.57 x 5 = 7.85. 11.84 - 7.85 = 3.99, which it is not 3.39 => Cross D answer.
Therefore the cost of tacos need to be 1.69 because there have been a repetition in both A& C
1.69 x 5 = 8.45. $11.84 - 8.45 = $3.39 for quesadillas.
Which it proves for the answer is C
Hope I have helping you on this question
Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
33+9= 42+12= 54+2=90-56= 34 34+3x
I don't know
Given:
In 2010, the population of a town = 2000
Every year, it increase by 1.5%
To find the equation P(t) which represents the population of this town t years from 2010.
Formula
If a be the original population of a town and it increases by b% every year, after t year the population will be
Now,
Taking, a =2000, b = 1.5 we get,
or, 
Hence,
The population of this town t years from 2010 P(t) = 
, Option D.
