Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
Answer:
read.....
Step-by-step explanation:
Answer:
30
Step-by-step explanation:
94-64=30 will offer the same course because the chemistry offers ocerride the mathematics offers
Answer:
72 +1 , If u = A 8 1 - 2 ( ( + + +1 )– flog ( 3 + 3 / 3 ) ? v1m * + n + 13 ) 4 1 ; then 2 If c ... of any number of such MATHEMATICS . triangles ; and ( 3 ) find the mean value of ... 72 = 62 + 69 , 73 = 82 + 39 , 75 = 72 + 52 . the in - centre and centroid . ... 4n + 1 , or 4n + 2 ,
Step-by-step explanation:
