Answer:
The volume of the ball with the drilled hole is:
Step-by-step explanation:
See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:
Then we set the integral for the volume by using shell method:
That can be solved by substitution:
The limits of integration also change:
For x=5: 
For x=15: 
So the integral becomes:
If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:
Then applying the basic rule we get:
Since that is just half of the solid, we multiply by 2 to get the complete volume:
Answer:
mp=2800
mp=cp+40%ofcp=cp+40/100×cp=1.4cp
2800=1.4çp
cp=2800/1.4=2000
discount=20%
profit%=?
Step-by-step explanation:
sp=mp-discount%of mp=2800-20/100×2800=2240
profit=sp-cp=2240-2000=240
profit%=profit/cp×100%=240/2000×100%=12%
Since we know that there are exactly 180 degrees in any triangle, and if each angle is equal to 45 degrees, we must add 45 to 45 and then subtract the result from 180 to find the 3rd angle. Since 45+45=90,we subtract 180-90 and get 90 degrees or a right angle.
Start with the equation of a circle whose center is at (h,k) and whose radius is r:
(x-h)^2 + (y-k)^2 = r^2
Substituting the given coordinates of the center:
(x-5)^2 + (y-[-5])^2 = r^2, or (x-5)^2 + (y+5)^2 = r^2
Substituding the given coordinates of a point (6,-2) on the circle:
(6-5)^2 + (-2+5)^2 = r^2
Simplifying:
1^2 + 3^2 = r^2, or 1 + 9 = r^2, or 10= r^2. Then r = sqrt(10).
