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3 years ago

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Toni rides the Ferris wheel shown for 15 revolutions. A photo of a Ferris wheel has the diameter labeled fifty-six feet. Questio

n 1 Part A How far does Toni travel in one revolution? Use 227 for π

1 answer:

NARA [144]3 years ago

5 0

Answer:

a. 176 feet b. 2640 feet

Step-by-step explanation:

a. Since the diameter of the Ferris wheel is D = 56 feet, the distance Toni travels in one revolution is the circumference of the Ferris wheel, C = πD.

So C = 22/7 × 56 ft = 22 × 8 ft = 176 feet

b. The distance traveled in 15 revolutions is thus D' = 15 × distance of one revolution = 15 × 176 = 2640 feet

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Use the definition of Taylor series to find the Taylor series, centered at c, for the function. f(x) = sin x, c = 3π/4

anyanavicka [17]

Answer:

$\sin(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

Step-by-step explanation:

Given

$f(x) = \sin x\\$

$c = \frac{3\pi}{4}$

Required

Find the Taylor series

The Taylor series of a function is defines as:

$f(x) = f(c) + f'(c)(x -c) + \frac{f"(c)}{2!}(x-c)^2 + \frac{f"'(c)}{3!}(x-c)^3 + ........ + \frac{f*n(c)}{n!}(x-c)^n$

We have:

$c = \frac{3\pi}{4}$

$f(x) = \sin x\\$

$f(c) = \sin(c)$

$f(c) = \sin(\frac{3\pi}{4})$

This gives:

$f(c) = \frac{1}{\sqrt 2}$

We have:

$f(c) = \sin(\frac{3\pi}{4})$

Differentiate

$f'(c) = \cos(\frac{3\pi}{4})$

This gives:

$f'(c) = -\frac{1}{\sqrt 2}$

We have:

$f'(c) = \cos(\frac{3\pi}{4})$

Differentiate

$f"(c) = -\sin(\frac{3\pi}{4})$

This gives:

$f"(c) = -\frac{1}{\sqrt 2}$

We have:

$f"(c) = -\sin(\frac{3\pi}{4})$

Differentiate

$f"'(c) = -\cos(\frac{3\pi}{4})$

This gives:

$f"'(c) = - * -\frac{1}{\sqrt 2}$

$f"'(c) = \frac{1}{\sqrt 2}$

So, we have:

$f(c) = \frac{1}{\sqrt 2}$

$f'(c) = -\frac{1}{\sqrt 2}$

$f"(c) = -\frac{1}{\sqrt 2}$

$f"'(c) = \frac{1}{\sqrt 2}$

$f(x) = f(c) + f'(c)(x -c) + \frac{f"(c)}{2!}(x-c)^2 + \frac{f"'(c)}{3!}(x-c)^3 + ........ + \frac{f*n(c)}{n!}(x-c)^n$

becomes

$f(x) = \frac{1}{\sqrt 2} - \frac{1}{\sqrt 2}(x - \frac{3\pi}{4}) -\frac{1/\sqrt 2}{2!}(x - \frac{3\pi}{4})^2 +\frac{1/\sqrt 2}{3!}(x - \frac{3\pi}{4})^3 + ... +\frac{f^n(c)}{n!}(x - \frac{3\pi}{4})^n$

Rewrite as:

$f(x) = \frac{1}{\sqrt 2} + \frac{(-1)}{\sqrt 2}(x - \frac{3\pi}{4}) +\frac{(-1)/\sqrt 2}{2!}(x - \frac{3\pi}{4})^2 +\frac{(-1)^2/\sqrt 2}{3!}(x - \frac{3\pi}{4})^3 + ... +\frac{f^n(c)}{n!}(x - \frac{3\pi}{4})^n$

Generally, the expression becomes

$f(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

Hence:

$\sin(x) = \sum\limit^{\infty}_{n = 0} \frac{1}{\sqrt 2}\frac{(-1)^{n(n+1)/2}}{n!}(x - \frac{3\pi}{4})^n$

3 0

2 years ago

The speed of light is approximately 299,000,000 meters per second.

jek_recluse [69]

Answer:

2.99 x 10⁸ meters per second

Step-by-step explanation:

Scientific notation (also called "Standard form") is written in the form of $a \times 10^n$ , where $1\leq a < 10$ and $n$ is any positive or negative whole number.

To <u>convert</u> a number into <u>scientific notation</u>, move the decimal point to the left or right until there is <u>one digit before the decimal point.</u>

The number of times you have moved the decimal point is the power of 10 ( $n$ ).

If the decimal point has moved to the <u>left</u>, the power is <u>positive</u>.

If the decimal point has moved to the <u>right</u>, the power is <u>negative</u>.

<u>To convert the given number to scientific notation</u>

The decimal point for the given number 299000000 is after the last zero:

⇒ 299000000.

Move the decimal point 8 places to the left:

⇒ 2.99000000

Get rid of the redundant zeros:

⇒ 2.99

Multiply by 10 to the power of the number of decimal places moved:

⇒ 2.99 x 10⁸

Therefore, the speed of light using scientific notation is:

2.99 x 10⁸ meters per second

7 0

2 years ago

Lilly saw a jelly fish at 6 feet below sea level. She saw a bright blue fish at 10 feet below sea level. What is the distance be

Greeley [361]

Answer:

4 feet of distance between each other it is very simple and easy.

Step-by-step explanation:

They are both 6 feet and 10 feet away from each other so you just take 10-6 which is 4

3 0

3 years ago

Prime factorization of:<br><br><br> 1,000

AlladinOne [14]

Answer:

2 × 2 × 2 × 5 × 5 × 5

4 0

3 years ago

Henry buys a large boat for the summer, however he cannot pay the full amount of $32,000 at

Anna007 [38]

Answer:

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

Step-by-step explanation:

Loan payment per month=Amount to pay÷discount factor

Mathematically P=A÷D

where D is the discount factor calculated using the formula;

$\frac{(1+i)^n-1}{i(1+i)^n}$

where i=periodic interest rate=annual rate divided by number of payment periods

A is the amount to pay after downpayment

P is the loan monthly payment amount

n=number of periodic payments=payments per year times number of years

⇒In this question you find the discount factor then divide the amount remaining to pay with the discount factor to get monthly payments

Given;

Cost of boat=$32000

Down payment=$14000

Loan to pay=$32000-$14000=$18000

Annual rate=5.5%=i=5.5%÷12=0.458%⇒0.00458

Periodic payments, n=4×12=48

Finding the discount factor D;

$D=\frac{(1+i)^n-1}{i(1+i)^n} \\\\\\D=\frac{(1+0.00458)^{48} -1}{0.00458(1+0.00458)^{48} } \\\\\\D=\frac{1.2455-1}{0.005703} \\\\\\D=\frac{0.2455}{0.005703} =43.05$

To get the amount to pay monthly divide the loan to pay with the discount factor

$=\frac{18000}{43.05} =418.14$

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

8 0

3 years ago