Answer:
16 hours
Step-by-step explanation:
let t be time, n the number of computers and w the number of workers, then
t = ← k is the constant of variation
To find k use the condition n = 30, w = 6 and t = 10 , then
10 = ( multiply both sides by 6 )
60 = 30k ( divide both sides by 30 )
2 = k
t = ← equation of variation
When w = 5 and n = 40 , then
t = =
= 16 hours
Only p(x) has an average rate of change of -4 over [-2, 2].
Find the average rate of change of each given function over the interval [-2, 2]]:
The average rate of change of m(x) over [-2, 2]:
<h3>What is the average rate?</h3>The average rate of change =
Where, a = -2, m(a) = -12
b = 2, m(b) = 4
Plug the values into the equation
The average rate of change
The average rate of change = 4
The average rate of change of n(x) over [-2, 2]:
The average rate of change =
Where, a = -2, n(a) = -6
b = 2, n(b) = 6
Plug the values into the equation
The average rate of change
The average rate of change = 3
The average rate of change of q(x) over [-2, 2]:
The average rate of change =
Where, a = -2, q(a) = -4
b = 2, q(b) = -12
Plug the values into the
The average rate of change =
=
The average rate of change = -2
The average rate of change of p(x) over [-2, 2]:
The average rate of change =
Where, a = -2, p(a) = 12
b = 2, p(b) = -4
Plug the values into the equation
The average rate of change =
The average rate of change = -4
The answer is D.
Only p(x) has an average rate of change of -4 over [-2, 2].
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