Prime factorization of:<br><br><br> 1,000

Can someone tell me the answer please?

vovikov84 [41]

6.241 I think that's right

4 0

3 years ago

Please help and I will give brainliest if u do.

kirill115 [55]

Answer:

See explanation below

Step-by-step explanation:

The width is 4 inches

So, the area of the base is 20 inches squared

The height is 4 inches

So, the volume of the prism is 80 inches cubed

3 0

3 years ago

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D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

What’s the answer to number 19??

Igoryamba

The answer equals 6.

Since 3 3/4 equals 15/4, when you divide you have to switch the numbers in the divisor and then you turn the equation into multiplication.

So then it will be 15/4 x 4/3.

15 x 4 = 60

4 x 3 = 12 so the answer is 60/12. But you have to simplify so half of 60/12 is 30/6 and then half of 30/6 is 15/3 then you have to pick the gcf of 3 and 15 which is 3.

15 divided by 3 equals 5.

3 divided by 3 equals 1 so 5/1 equals 5

Hope this helps! ;)

5 0

3 years ago

If g(x)=a x f(x+b) how is f(x) transformed to get g(x)

guajiro [1.7K]

Answer:

Ok, we know that g(x) = a*f(x + b), we want to find all the transformations that we must apply to f(x) to construct g(x).

Let's assume at the beggining that T2(T1(f(x))) = g(x), and start appliying the transformations.

First, we have a horizontal shift.

If we want to move the graph A (A positive) units to the right, we should have:

g(x) = f(x - A)

in this case we have

g(x) = f(x + b) = f(x - (-b))

So we have a shift of -b units to the right, or b units to the left.

Second:

We have a vertical contraction/dilation.

if we have a function f(x), a compression/dilation of scale factor A is written as:

g(x) = A*f(x)

if A > 1, we have a dilation.

if 0 < A < 1, we have a contraction.

In this case the scale factor is a.

g(x) = a*f(x).

Now, applying both transformations we have:

> shift of b units to the left.

> contraction/dilation of scale factor a.

g(x) = a*f(x +b)

4 0

3 years ago

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Prime factorization of: 1,000