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3 years ago

The length of a rectangle is seven more than double the width. If the perimeter is 22 inches find the dimensions

Mathematics

1 answer:

lubasha [3.4K]3 years ago

7 0

Answer:

width = 1 1/3 inches

length = 9 2/3 inches

Step-by-step explanation:

let 'w' = width

let '7+2w' = length

P = 2l + 2w

22 = 2w + 2(7+2w)

22 = 2w + 14 + 4w

8 = 6w

w = 4/3 or 1 1/3

substitute 1 1/3, or 4/3, to find length:

l = 7 + 2(4/3)

l = 7 + 8/3 or 9 2/3

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Keywords: Conversions, Lengths

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4 years ago

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Step-by-step explanation:

Given the sequence

$a_1=-\dfrac{1}{3}\\ a_i=a_{i-1}\cdot (-3)$

$a_2=a_{2-1}\cdot (-3)=a_1 \cdot (-3) = -\dfrac{1}{3}\cdot (-3)=1\\a_3=a_{3-1}\cdot (-3)=a_2 \cdot (-3) = 1 \cdot (-3)=-3\\a_4=a_{4-1}\cdot (-3)=a_3 \cdot (-3) = -3 \cdot (-3)=9\\$

Therefore the sequence is:

$-\dfrac{1}{3}, 1, -3, 9, ...$

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First Term, $a_1=-\dfrac{1}{3}$

Common ratio, r =-3

We want to determine the sum of the first 75 terms.

For a geometric sequence, the sum:

$S_n=\dfrac{a_1(1-r^n)}{1-r} \\$

Therefore:

$S_{75}=\dfrac{-\dfrac{1}{3}(1-(-3)^{75})}{1-(-3)} \\\\=\dfrac{-(1-(-3)^{75})}{4*3}\\\\S_{75}=\dfrac{(-3)^{75}-1}{12}\\\\S_{75}=-506.888989761$ X 10^{32}$

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3 years ago