<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
Answer:
B and C
(I'm not sure if b and e are supposed to be the same though) if they are then, b, c, and e
<span>6840 customers ... 45 days<span>
x customers = ? ... 1 day
If you
would like to know how many customers were in Jasigreen's class in 1 day,
you can calculate this using the following steps:
6840 * 1 = 45 * x
6840 = 45
* x /45
x = 6840 / 45
x = 152 customers
<span>The
correct result would be </span>152 customers<span>.</span></span></span>
The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.
<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>
To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:
We need to find 37% of 55 as shown below:
- 55 ÷ 100 = 0.55
- 0.55 x 37% = 20.35
- 55 + 20.35 = 75.35
So after 2 days I will have 75.35 microorganisms.
- 75.35 ÷ 100 = 0.75
- 0.7535 x 37% = 27.87
- 75.35 + 27.87 = 103.22
On the fourth day I will have: 103.22 microorganisms.
- 103.22 ÷ 100 = 1.0322
- 1.0322 x 37% = 38.19
- 103.22 + 38.19 = 141.41
On the sixth day I will have 141.41 microorganisms.
- 141.41 ÷ 100 = 1.4141
- 1.4141 x 37% = 52.32
- 141.41 + 52.32 = 193,73
On the eighth day I will have 193.73 microorganisms.
- 193.73 ÷ 100 = 1.9373
- 1.9373 x 37% = 71.68
- 193.73 + 71.68 = 265.41
On the tenth day I will have 245.41 microoganisms.
Learn more about percentages in: brainly.com/question/13450942
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