The formula for infinite geometric series is equal to a1 / (1-r) where in this problem a1 is equal to 8 and r is equal to 4. In this case, r is not equal to less than 1. This means the sum should be infinity and cannot be determined definitely.
I think the answer would be 5
Answer:
The other 3 numbers you are looking for are:
24/11
84/11
96/11
Step-by-step explanation:
We can start off by making the numbers 2x, 7x, and 8x. We put them in expressions:
(7x-12)^2=2x(8x)
Simplify
49x^2-168x+144=16x^2
Subtract 16x^2 on each side
33x^2-168x+144=0
Divide by 3
11x^2-56x+48=0
Factor
(11x-12)(x=4)=0
Answer
x=4 or x=12/11
If x is equivalent to 4 then that means that the original numbers would be:
8, 28, 32
2(4), 7(4), 8(4)
Subtracting 12 from Y, or 28 will make it 16.
8, 16, 32
This seems to be a geometric progression
Next we have 12/11
2(12/11), 7(12/11), 8(12/11)
24/11, 84/11, 96/11
Subtracting 12 from Y, or 84/11 will get us -48/11, meaning r=-2 for the GP.
Final Answer:
8 , 28 , 32
24/11 , 84/11 , 96/11
