Answer:
A
Step-by-step explanation:
Answer:
4 cents
Step-by-step explanation:
4.50 divide by is .9 and 7.52 divide by 8 is .94
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Answer: 3.66 cm
Step-by-step explanation: Given a rectangular casing BCDE with segment DE = 3 cm and segment BE = 3.5 cm.
The area A of a rectangle is length multiply by width.
Where length L = 3.5 cm and
width W = 3 cm
Area A = 3.5 × 3 = 10.5 cm^2
The pipe that will fit the fiber optic line is in cylindrical shape. Where area of a cylinder = πr^2.
But area A = 10.5. Substitute the values for the area of the cylinder
10.5 = πr^2
10.5 = 3.143 × r^2
Make r^2 the subject of formula
r^2 = 10.5/3.143
r = sqrt ( 3.34225 )
r = 1.828
Diameter = 2 × radius
Diameter = 2 × 1.829
Diameter = 3.656 cm
Therefore, the smallest diameter of pipe that will fit the fiber optic line is 3.66 cm approximately.
Answer:
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)
Step-by-step explanation:
we have
![f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
![g(x)=\frac{1}{x^{2}+1}](https://tex.z-dn.net/?f=g%28x%29%3D%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D)
we know that
In the function
![f(g(x))](https://tex.z-dn.net/?f=f%28g%28x%29%29)
The variable of the function f is now the function g(x)
substitute
![f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%7D%7D)
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)