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Mashutka [201]
3 years ago
9

$31.40 and $5 in slope intercept form

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

y=31.40x+5

Step-by-step explanation:

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Find the HIGHEST Common<br> and lowest common multple<br> of 36 and 48 using<br> prime factors
Vesnalui [34]

Answer:

Step-by-step explanation:

Least common multiple can be found by multiplying the highest exponent prime factors of 36 and 48. First we will calculate the prime factors of 36 and 48.

Prime Factorization of 36

Prime factors of 36 are 2, 3. Prime factorization of 36 in exponential form is:

36 = 22 × 32

Prime Factorization of 48

Prime factors of 48 are 2, 3. Prime factorization of 48 in exponential form is:

48 = 24 × 31

Now multiplying the highest exponent prime factors to calculate the LCM of 36 and 48.

LCM(36,48) = 24 × 32

LCM(36,48) = 144

List of positive integer factors of 36 that divides 36 without a remainder.

1, 2, 3, 4, 6, 9, 12, 18

Factors of 48

List of positive integer factors of 48 that divides 36 without a remainder.

1, 2, 3, 4, 6, 8, 12, 16, 24

Greatest Common Factor Number

We found the factors and prime factorization of 36 and 48. The biggest common factor number is the GCF number.

So the greatest common factor 36 and 48 is 12.

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3 years ago
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X+2y-z=5<br> -X-y+2z=-13<br> 2x+y-2z=14
faltersainse [42]

Answer:

x+2y-z=5 ...(1)\\ -x-y+2z=-13...(2) \\ 2x+y-2z=14...(3) \\  \\ add \: (2) + (3) \\\boxed{x= 1} \\ 2 \times (1) + (2) \\ x + 3y =  - 3 \\ 1 + 3y =  - 3 \\ 3y =  - 4 \\ \boxed{y =  -  \frac{4}{3}  }\\ solve \: for \: z \\ x + 2y - z = 5  \\ 1-\frac{4}{3}(2)-z=5\\3-8-3z=15\\3z=-20\\\boxed{z = -   \frac{20}{3} }

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What are the period P and frequency T of oscillation of a pendulum of length one half​ft? (Hint: Upper P equals 2 pi StartRoot S
guajiro [1.7K]

Answer:

P'=P \sqrt{\dfrac{1}{2}}

T ' = √2 T

Step-by-step explanation:

Given that

Time period = P

Frequency = T

We know that time period for pendulum given as

P=2\pi \sqrt{\dfrac{L}{g}}

When the length become half then time period will become p'

L'=L/2

P'=2\pi \sqrt{\dfrac{L'}{g}}

P'=2\pi \sqrt{\dfrac{L}{2g}}

P'=P \sqrt{\dfrac{1}{2}}

It means that time period will become 0.707 P.

We know that frequency T

T= 1 /P

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