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3 years ago

What is one sixth of 24

Mathematics

2 answers:

iren [92.7K]3 years ago

7 0

I neede help to go this promblem 3/8 * 8 8/12 and i'm stuck

alisha [4.7K]3 years ago

5 0

This is equivalent to dividing 24 by 6 or to solving for x in the following equation: 6x=24. The answer, in both cases, is 4.

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If the office furniture costs $9,900 and it was three times as expensive as the office computer, what was the cost of the comput

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Answer: 3,300

Step-by-step explanation:

9,900÷3

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3 years ago

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How do I solve this equation and check the solutions?

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Answer:

Step-by-step explanation:

1. 8x8=64

2.64-20=44

Answer; 44

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2 years ago

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9. Jina stated that there is one dilation that creates congruent figures. Is she correct?

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Explanation:
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3 years ago

GETS BRAINILIST!!!A class has 6 boys and 14 girls. What is the ratio in simplest form that compares number of boys to total numb

FinnZ [79.3K]

Answer:

3:10

Step-by-step explanation:

1. Find the total number of students by doing

14 + 6= 20

2. Now make your ratio

6:20

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20 divided by 2 is 10

4. Your answer is

3:10

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3 years ago

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Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

$SE = 0.66}$

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

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3 years ago