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STALIN [3.7K]
3 years ago
9

What is one sixth of 24

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0
I neede help to go this promblem 3/8 * 8 8/12 and i'm stuck
alisha [4.7K]3 years ago
5 0
This is equivalent to dividing 24 by 6 or to solving for x in the following equation: 6x=24. The answer, in both cases, is 4.
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If the office furniture costs $9,900 and it was three times as expensive as the office computer, what was the cost of the comput
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Step-by-step explanation:

9,900÷3

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How do I solve this equation and check the solutions?
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44

Step-by-step explanation:

1. 8x8=64

2.64-20=44

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9. Jina stated that there is one dilation that creates congruent figures. Is she correct?
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GETS BRAINILIST!!!A class has 6 boys and 14 girls. What is the ratio in simplest form that compares number of boys to total numb
FinnZ [79.3K]

Answer:

3:10

Step-by-step explanation:

1. Find the total number of students by doing

14 + 6= 20

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6:20

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6 divided by 2 is 3

20 divided by 2 is 10

4. Your answer is

3:10

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3 years ago
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Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
3 years ago
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