Question

In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?

Answer 1

Answer:   6π

Step-by-step explanation:

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.

$A=\pi r^2\bigg(\dfrac{\theta}{360^o}\bigg)$

Given: r = 6, Ф = 60°

$A=\pi (6)^2\bigg(\dfrac{60^o}{360^o}\bigg)\\\\\\.\quad =\pi (6)^2\bigg(\dfrac{1}{6}\bigg)\\\\\\.\quad =6\pi$