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3 years ago

Molly buys a scooter for $26.99. Robert buys a basketball for $12.89. How much more does Molly spend more money than Robert?

Mathematics

1 answer:

erastovalidia [21]3 years ago

7 0

Molly spends 14.10 more on her scooter. I did this by doing 26.99 - 12.89.

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Which of the following equations is written in standard form?

Harlamova29_29 [7]

Standard Form is ax + by = c, where a, b, and c are not fractions and a is not negative.

So, you can go through each of your options to see which ones work with those rules.

A. 2.5x + 3y = 12 No, this is not in Standard Form. 2.5 can be rewritten as 2 $\frac{1}{2}$ , menaing A is a fraction, which you can't have.

B. -10x - 3y = 1 No, this is not in Standard Form. A is -10, but A can't be negative.

C. 2x + 3y = 12 Yes, this is in Standard Form. It follows all of the rules.

D. 5x + 5y = 10 Yes, this is in Standard Form. It follows all of the rules.

So, C and D are both written in Standard Form.

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A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa

diamong [38]

Answer:

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}= \mu_D$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C,D$

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p=4$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

$p_v= 0.01$

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your answer

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