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3 years ago

What is the value of the expression shown below?

Mathematics

2 answers:

Nitella [24]3 years ago

5 0

Answer:

$10\frac{9}{25}$

Step-by-step explanation:

$(\frac{3}{5})^2 + 4 * 3 - 2$

Simplify the given expression

WE use order of operation PEMDAS

Parenthesis, exponents, multiply , divide , add and subtract

LEts start with parenthesis

$(\frac{9}{25})+ 4 * 3 - 2$

now we multiply

$(\frac{9}{25})+12 - 2$

now subtract 2

$(\frac{9}{25})+10$

This can be written as $10\frac{9}{25}$

lesya692 [45]3 years ago

4 0

(3/5)^2 + 4 × 3 - 2
9/25 + 12 - 2
9/25 + 10
It would be 10 and 9 over 25

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A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul

pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

$\hat p$ = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.6858

n = sample of respondents = 2,610

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at

2.5% level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $0.6858-1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} }$ , $0.6858+1.96 \times {\sqrt{\frac{0.6858(1-0.6858)}{2610} }$ ]

= [0.668 , 0.704]

Therefore, 95% confidence interval for the population proportion of the adults is (0.668, 0.704).

3 0

3 years ago

Subtract and add the group of fractions below. Make sure the answer is fully reduced.

yarga [219]

Answer:

19/20 that's simplified by the way... and if you want the decimal form it's 0.95

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3 years ago

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3 years ago

If Kara's cat weighs 15 pounds and Molly's cat weighs 8 pounds, how much heavier is Kara's cat than Molly's cat? 7

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Answer:

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Step-by-step explanation:

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2 years ago

I really need help! I'm stuck.

Dovator [93]

y-axis = altitude in feet

x-axis = minutes

slope = y/x = feet/minute

According to above data, we know that 1800 feet is y-intercept and slope is -300 feet per minute (why slope is negative? because its approaching ground at a constant speed)

a. slope = -300

y-intercept = 1800

b. y = -300 x + 1800

c. Here we are given x = 2 minutes

y = -300(2) + 1800

y = -600 + 1800

y = 1200

The balloon will be 1200 feet high above the ground in 2 minutes.

d. Here we are given 300 feet which is y, and find x minutes.

y = -300 x + 1800

300 = -300x + 1800

300 - 1800 = - 300x

-1500 = -300x

1500 = 300 x

x = 1500 / 300

x = 5

The balloon will reach 300 feet above the ground in 5 minutes.

e. It asking when the balloon will reach the ground, if the balloon reaches the ground than the height will be 0, therefore x-intercept (y=0).

y = -300 x + 1800

0 = -300 x + 1800

-1800 = -300x

1800 / 300 = x

x = 6

The balloon will reach the ground in 6 minutes.

//Hope this helps

3 0

3 years ago