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olya-2409 [2.1K]
3 years ago
11

A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence interval for the proportion of homeles

s persons who are veterans.
Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

[0.184, 0.266]

Step-by-step explanation:

Given:

Number of survey n =280

Number of veterans = 63

Confidence interval = 90%

Computation:

Probability of veterans = 63/280

Probability of veterans =0.225

a=0.1

Z(0.05) = 1.645 (from distribution table)

Confidence interval = 90%

So,

p ± Z*√[p(1-p)/n]

0.225 ± 1.645√(0.225(1-0.225)/280)

[0.184, 0.266]

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