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3 years ago

How to measure in inches for grade 2

Mathematics

1 answer:

Usimov [2.4K]3 years ago

8 0

Answer: Put your index finger and middle finger together

Step-by-step explanation: At that age your fingers are really skinny so they add up to a whole in. To measure a centimeter all you have to do is measure it with your pinky

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What is the value of x?

aev [14]

x= 18

let me show you the workout

6x+1+12x-5=32

Combine like terms .Combine 6x+12=18x

18x-4=32 Subtract -4 from 32

18x=36 Divide by 18 and

X=16

Hoped this helped Im not sure if this is right

8 0

2 years ago

Which of these people ran for about 35 minutes?

solniwko [45]

9514 1404 393

Answer:

D Malin ran from 3:42 PM until 4:17

Step-by-step explanation:

You need only examine the least-significant digits to determine of the difference of times will end in 5.

The only time difference that is 35 minutes is ...

3:42 pm to 4:17 pm . . . . . . choice D

7 0

2 years ago

Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)

Triss [41]

$g(r,\theta)=(r\cos\theta,r\sin\theta,\theta)\implies\begin{cases}g_r=(\cos\theta,\sin\theta,0)\\g_\theta=(-r\sin\theta,r\cos\theta,1)\end{cases}$

The surface element is

$\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta$

and the integral is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta$

$=\displaystyle2\pi\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac\pi4(132\sqrt{17}-\sinh^{-1}4)$

###

To compute the last integral, you can integrate by parts:

$u=r\implies\mathrm du=\mathrm dr$

$\mathrm dv=r\sqrt{1+r^2}\,\mathrm dr\implies v=\dfrac13(1+r^2)^{3/2}$

$\displaystyle\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac r3(1+r^2)^{3/2}\bigg|_0^4-\frac13\int_0^4(1+r^2)^{3/2}\,\mathrm dr$

For this integral, consider a substitution of

$r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds$

$\displaystyle\int_0^4(1+r^2)^{3/2}\,\mathrm dr=\int_0^{\sinh^{-1}4}(1+\sinh^2s)^{3/2}\cosh s\,\mathrm ds$

$\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds$

$=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds$

and the result above follows.

4 0

3 years ago

Solve for w in the equation w⁄5 = 25

Anarel [89]

we are given

$\frac{w}{5} =25$

Since, we have to solve for w

so, we will isolate w on anyone side

Multiply both sides by 5

$5*\frac{w}{5} =5*25$

$w =5*25$

$w =125$

so,

option-D..........Answer

7 0

3 years ago

Read 2 more answers

(Help)Find the value of X.<br> 15-18

Juliette [100K]

Answer:Tag 30*(2\/3)=x

Step-by-step explanation:

Tag 30*= x/2\/3;

Tag 30*(2\/3)=x

6 0

2 years ago