All categories

3 years ago

What is 10x10x10= pls help me

Mathematics

2 answers:

dem82 [27]3 years ago

6 0

Answer:

1,000

Step-by-step explanation:

plz mark brainliest

grigory [225]3 years ago

5 0

Answer: 1000

Step-by-step explanation:

You might be interested in

Find all values of θ in the interval 0° ≤ θ < 360° that satisfy the equation sin 2θ = sin θ.

kap26 [50]

Sin 2θ = sin θ
2sin θ cos θ = sin θ
2cos θ = 1
cos θ = 1/2
θ = arccos(1/2) = 60° and 300°
θ = 60° and 300°

7 0

3 years ago

Write an equivalence chain with fraction that equals 1/2

alexgriva [62]

Hi.

An example of a fraction equivalence chain is this:

$\frac{1}{2}, \frac{2}{4}, \frac{4}{8}, \frac{8}{16}, \frac{16}{32}$

You can keep multiplying $\frac{1}{2}$ by 2 to get a fraction chain.

Hope this helps!

7 0

3 years ago

In the figure below, ray was constructed starting from rays and . By using a compass D and G were marked equidistant from E on r

DaniilM [7]

The correct answer is that the angles created are equal.

The steps given are used to create an angle bisector of the angle. That means it divides the angle into 2 congruent angles.

6 0

4 years ago

Bhaskar went for hiking with scouts’ team and there the scouts were given a task to build tents with the help of bamboos, ropes

dimulka [17.4K]

The triangles on Bhaskar's tent are similar triangles.

The length of IJ is 4.5 m
The applicable theorem is the mid-point theorem
The appropriate formula for area is the Heron's formula
The ratio of ABC to DEF is 1 : 9

(a) The length of IJ

The given parameter are:

$\mathbf{EF = 9m}$

I and J are at the midpoint of DE and DF

The above highlight means that

$\mathbf{IJ= \frac 12 \times EF}$ --- midpoint theorem

Substitute 9 for EF

$\mathbf{IJ= \frac 12 \times 9m}$

$\mathbf{IJ= 4.5\ m}$

(b) The property used to find GH and IJ

In (a), the midpoint theorem is used to calculate IJ

GH and IJ are corresponding sides of similar triangles,

So the midpoint theorem can also be used to calculate the length of GH

(c) The area of the triangle

For the given triangles, the lengths of the sides are known.

When side lengths are known, the formula to use for finding the triangle's area is the Heron's formula.

The Heron's formula is:

$\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}$

Where:

$\mathbf{s = a + b + c}\\\mathbf{a,b,c \to sides\ of\ the\ triangle}$

(d): The ratio of the areas:

For the small triangle, we have:

$\mathbf{a= 3.8,\ b = 4,\ c = 3}$

So, we have:

$\mathbf{s = 3.8 + 4 + 3 = 10.8}$

So, the area is:

$\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}$

$\mathbf{A_{small} = \sqrt{10.8 \times (10.8 -3.8) \times (10.8 - 4) \times (10.8 - 3)}}$

$\mathbf{A_{small} = \sqrt{4009.824}}$

For the big triangle, we have:

$\mathbf{a= 11.4,\ b = 12,\ c = 9}$

So, we have:

$\mathbf{s = 11.4 + 12 + 9 = 32.4}$

So, the area is:

$\mathbf{Area = \sqrt{s \times (s -a) \times (s - b) \times (s - c)}}$

$\mathbf{A_{big} = \sqrt{32.4 \times (32.4 -11.4) \times (32.4 - 12) \times (32.4 - 9)}}$

$\mathbf{A_{big} = \sqrt{324795.744}}$

The ratio of the small triangle to the big triangle is:

$\mathbf{Ratio = A_{small} : A_{big}}$

$\mathbf{Ratio = \sqrt{4009.824}:\sqrt{324795.744}}$

Divide by 4009.824

$\mathbf{Ratio = \sqrt{1}:\sqrt{81}}$

Take square roots

$\mathbf{Ratio = 1 : 9}$

Hence, the ratio of ABC to DEF is 1 : 9

Read more about similar triangles at:

brainly.com/question/24874611

7 0

3 years ago

3.2] I can rearrange formulas to solve for a specified variable. Solve for r. h=r-m

Lesechka [4]

Answer:

r = h + m

Step-by-step explanation:

h = r - m

Switch sides.

r - m = h

Add m to both sides.

r - m + m = h + m

Simplify the left side. -m + m = 0

r = h + m

6 0

2 years ago