Answer:
<em>Answers below</em>
Step-by-step explanation:
<u>Equation</u>
Let's call:
p = number of pennies Janesa has in her pocket
n = number of nickels Janesa has in her pocket
She has 24 coins in total, thus:
![p + n=24\qquad\qquad [1]](https://tex.z-dn.net/?f=p%20%2B%20n%3D24%5Cqquad%5Cqquad%20%5B1%5D)
Since each penny is worth $0.01 and each nickel is worth $0.05, and Janesa has $1 in total:
Multiplying by 100:
![p+5n=100\qquad\qquad [2]](https://tex.z-dn.net/?f=p%2B5n%3D100%5Cqquad%5Cqquad%20%5B2%5D)
A. Completing the equation:
B.
From [1]:
Substituting into [2]:
Simplifying:
Rearranging:
B. There are 5 pennies in Janesa's pocket
C. Since each penny is worth $0.01, the total value of pennies is 5*$0.01=$0.05
The total value of the pennies is $0.05
D. The total value of the nickels is 19*$0.05 = $0.95
E. Jackson should say she has 19 nickels and 5 pennies
Five sos tha of sum of three. = -237.5
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
2x^3 +14x^2 -13x-3
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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