Applying the segment addition theorem, the length of line segment VW is: 2 units.
<h3>What is the
Segment Addition Theorem?</h3>
The segment addition theorem states that the sum of the lengths of two segments that make up a larger line segment equals the measure of the larger line segment, if the point on the line segments are collinear.
UV = 8x
VW = x+1
UW = 10
UV + VW = UW (segment addition theorem)
Substitute the values
8x + (x + 1) = 10
Open bracket
8x + x + 1 = 10
Combine like terms
9x + 1 = 10
Subtract 1 from both sides
9x + 1 - 1 = 10 - 1
9x = 9
Divide both sides by 9
9x/9 = 9/9
x = 1
VW = 8x + (x + 1)
Plug in the value of x
VW = x + 1
VW = 1 + 1
VW = 2 units.
Therefore, applying the segment addition theorem, the length of line segment VW is: 2 units.
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4/16 and 1/4 happy to help :)
7a^3(6a^2 + a)^2 - 4a^6
All we have to do here is basically add and subtract exponents!
(6a^2 + a)^2 = 36a^4 + a^2
7a^3(36a^4 + a^2) - 4a^6
252a^7 + 7a^5 - 4a^6
Answer is C.
Answer:
36
Step-by-step explanation:
Let number of m&ms Garry has be g
number of m&ms Larry has be l
Number of m&ms Jerry has be j
Since Gary has TWICE as Larry, we can write:
g = 2l
Also, Jerry has THRICE as Larry, we can write:
j = 3l
Together, they have 108, thus, we can write:
g + l + j = 108
Putting 1st and 2nd equation in 3rd, we can solve for Larry first. Shown below:
Larry has 18. To find Gary's number, we can use the fact g = 2l, so
g = 2 * 18 = 36
Gary has 36 m&ms
Answer:
Step-by-step explanation:
You have to group all of the same one's together and however many there is, you add that number as the exponent.
There were 2 "(-2)" so that became 
, and there were 5 "7" so that became 
. You keep the symbol and put it together which became
