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Greeley [361]
2 years ago
9

Find the quotient. Write your answer as a mixed number with your fraction in simpliest form.

Mathematics
2 answers:
Likurg_2 [28]2 years ago
8 0

Answer:

327 1/3 that should do it.

Step-by-step explanation:

mihalych1998 [28]2 years ago
4 0
327 1/3
Is simplified to 1/3 because it’s a run on
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Kobe has collected 750 football cards and 660 baseball cards. He wants to divide them into piles so that each pile has only one
Harrizon [31]

Answer: 30 cards

Step-by-step explanation:

To find the greatest possible number of cards in each pile such that there is the same number of cards in each​ pile we need to find the greatest common factor of 750 and 660.

Using Euclid division method , we have

750=1(660)+90\\\\660=7(90)+30\\\\90=3(30)+0

Hence, the greatest common factor of 750 and 660 = 30

Thus, there will be 30 cards in each pile.

4 0
3 years ago
For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger
11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = p=\frac{1}{120}.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419

6 0
3 years ago
Analyze the scatterplot below, what prediction can you make about the group of students used in the study from the graph below?
SCORPION-xisa [38]

Answer:

i do not understand

Step-by-step explanation:

8 0
2 years ago
Identify the domain and the range <br> (1,-4),(2,-3,),(3,-2),(4,1),(5,0)
horsena [70]
The domain is the x value and the range is the y value DOMAIN: {1, 2, 3, 4, 5} RANGE: {-4, -3, -2, -1, 0}
3 0
3 years ago
Triangle XYZ is reflected over its hypotenuse to create a kite.
galben [10]

The angle between line XZ and line XY is given by:

x = atan (\frac{12}{5})\\x = 67.38

Then, the height from vertex Y to horizontal line XZ is:

h = 5 sine (67.38)\\h = 4.62

Then, the distance from Y to Y 'is given by:

YY '= 2h\\YY '= 2 (4.62)\\YY '= 9.2

Answer:

the approximate distance from Y to Y 'is:

D. 9.2 units

3 0
3 years ago
Read 2 more answers
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