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3 years ago

13

Bill and 10 friends are planning for a pizza party.They purchased 3 quarts of juice.If each glass holds 8 ounces will everyone g

et at least one glass of juice?Show your work.

1 answer:

Naily [24]3 years ago

7 0

Yes. all the friends will get at least one cup of juice

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Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

2 years ago

Set up a table of values and then graph the line from its parametric form.. x=8+4t. y=-1+8t

Shalnov [3]

<span> x=8+4t

y=-1+8t

t = 0 x = 8 y = -1
</span>
t = 1 x = 12 y = 7

t = 2 x = 16 y = 15

7 0

3 years ago

Read 2 more answers

If $3 million is invested at 6% interest compounded continuously how much will the investment be worth in 35 years

Bogdan [553]

<span>P=$3000000 , r=6% , n=365 and t=35 years

</span>A= 3000000 (1 +0.06/365)³⁶⁵ˣ³⁵
A= 3000000 * 1.000164¹²⁷⁷⁵
A= 3000000 * <span>8.124858
A= 24374574

</span>A = P+<span>I
</span><span>2437457.4 </span><span><span>=3000000+I
</span><span><em />I =2437457.4−3000000
</span><span>I =21374574</span></span>

8 0

3 years ago

Which one is not a function? And why not ?

stira [4]

Answer:

the selected answer/2

Step-by-step explanation:

not a function because the same y has 2 different x values

8 0

2 years ago

How do we show where an inequality is true on the number line! 50 points!

Vinvika [58]

Usually, we use the number line to solve inequalities with the symbols, < , ≤ , > , and ≥ .(the second and last one was rather hard to find on my keyboard) In order to solve an inequality using the number line, though, just turn the inequality sign to an equal sign. Then, solve the equation. Next step, graph the point on the number line (remember to graph as an open circle if the original inequality was <, or >). The number line should now be divided into 2 regions, one to the left of the graphed point, and one to the right of said point.

After that, pick a point in both regions and "test" it, check to see if it satisfies the inequality when plugged in for the variable. If it does, draw a darker line from the point into that region, with an arrow at the end. That is the solution to the equation: if one point in the region satisfies the inequality, the entire region will satisfy the inequality.

I had to check back in an old textbook to remember all of that. Sorry about the earlier answer. That was rather foolish to do so without actually understanding the question.

3 0

3 years ago