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lubasha [3.4K]
3 years ago
15

15 is what percent of 20

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0
100%/x%=20/15
(100/X)*x=20/15*x   --I multiply both sides of the equation by X
100=1.33333333333*x --I divided both sides of the equation by                     .........................................(1.33333333333) to get X
100/1.33333333333=x
75=x
x=75

15 is 75% of 20

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Lesechka [4]

Given:

3x - 2

To find:

Describe the parts of the expression

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comparing the given equation with straight line equation, we get,

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3 0
2 years ago
Alexis recieved an 85,89,92on three tests.How many points does she need to score on her next test in order to have an average of
Vladimir [108]
94

(85+89+92+x)/4 = 90

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5 0
3 years ago
Read 2 more answers
The number of bacteria in a refrigerated food product is given by N ( T ) = 27 T 2 − 180 T + 100 N(T)=27T2-180T+100, 7 < T &l
NeX [460]

Answer:

N(T(t))=432t^2-374.4t-118.88

The number of Bactria after 5.8 hours is 12242.

Step-by-step explanation:

The number of bacteria in a refrigerated food product is given by

N(T)=27T^2-180T+100

where, T is the temperature of the food.

When the food is removed from the refrigerator, then the temperature is given by

T(t)=4t+1.6

We need to find the composite function N(T(t)).

N(T(t))=N(4t+1.6)

N(T(t))=27(4t+1.6)^2-180(4t+1.6)+100

N(T(t))=432t^2+345.6t+69.12-720t-288+100

N(T(t))=432t^2-374.4t-118.88

where N(T(t)) is the number of bacteria after t hours.

Substitute t=5.8 in the above function.

N(T(5.8))=432(5.8)^2-374.4(5.8)-118.88

N(T(5.8))=14532.48-2290.4

N(T(5.8))=12242.08

N(T(5.8))\approx 12242

Therefore, the number of Bactria after 5.8 hours is 12242.

7 0
3 years ago
What is the answer to this question?​
kvasek [131]

Answer:

Step-by-step explanation:

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7 0
3 years ago
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Mashcka [7]
Do you mean like this?

Y = -x - 4
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x = -2

Therefore y = -2
7 0
3 years ago
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