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3 years ago

5р + 3р + (-9) ? A. 8p+9 B. 3(p+(-3))+5p C. None of the above ...

Mathematics

1 answer:

kvv77 [185]3 years ago

3 0

Answer:

none of the above

Step-by-step explanation:

because 5p + 3p = 8p and positive integers × negative integers = negative integers.

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Vesna [10]

$(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =$

$= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}$

$= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}$

$= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}$

$= 2^{-16-12+28} \times 5^{10-8}$

$= 2^{0} \times 5^{2}$

$= 1 \times 25$

$= 25$

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3 years ago

G(x)=2x-2 <br> f(x)=x^2+3x <br> find (g of f)(2+x)

Bumek [7]

Answer:

Step-by-step explanation:

G(f(2+x))=g(2+x)^2+3(2+x)=2(2+x)^2+3(2+x)-2=2(4+4x+x^2)+6+3x=8+8x+2x^2+6+3x=2x^2+11x+14

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3 years ago

Find the absolute value of 2 and 2 3rd and negative 9 over 4

gayaneshka [121]

we are given

absolute value of 2 and 2 3rd and negative 9 over 4

Firstly , we need write it in terms of expression

2 and 2 3rd is

$2+\frac{2}{3}$

so, we get as

$|2+\frac{2}{3} -\frac{9}{4} |$

now, we can simplify it

Firstly , we will find common denominator

$|\frac{2*12}{1*12} +\frac{2*4}{3*4} -\frac{9*3}{4*3} |$

$|\frac{24}{12} +\frac{8}{12} -\frac{27}{12} |$

we can see that

all denominators are same

so, we can combine numerators

$=|\frac{24+8-27}{12} |$

$=|\frac{5}{12} |$

$=\frac{5}{12}$ ..............Answer

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4 years ago

5р + 3р + (-9) ? A. 8p+9 B. 3(p+(-3))+5p C. None of the above ...​

5р + 3р + (-9) ? A. 8p+9 B. 3(p+(-3))+5p C. None of the above ...