636/526 pls answer and you get points

If the correlation coefficient is .87, is its relationship considered to be strong positive,weak positive,strong negative,weak n

myrzilka [38]

Answer:

strong positive correlation co efficient

Step-by-step explanation:

<u>correlation:-</u>

A correlation co-efficient is a numerical measure of some type of correlation,meaning a statistical relationship between two variables.

<u>positive correlation:-</u>

Positive correlation occurs when an increase in one variable increases the value in another.

<u>Negative correlation:-</u>

negative correlation occurs when an increase in one variable decreases the value of another.

Strong positive correlation:-

A co-efficient of correlation of + 0.87 indicates a strong positive correlation between the independent variables

Strong negative correlation:-

A co-efficient of correlation of - 0.87 indicates a strong negative correlation between the independent variables.

Zero correlation:-

There is no relationship is called zero correlation

weak positive correlation:-

A co-efficient of correlation below 0.2 indicates a weak positive correlation between the independent variables.

weak negative correlation:-

A co-efficient of correlation below -0.2 indicates a weak negative correlation between the independent variables.

8 0

3 years ago

Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po

Olegator [25]

The expressions which represents the slope of a tangent to the curve $y=\frac{1}{x+1}$ at any point (x, y) are:

$f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}$

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

$f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}$

Given the function:

$f(x)=y=\frac{1}{x+1}$

When (x + h), we have:

$f(x+h)=y=\frac{1}{x+h+1}$

Next, we would find the derivative of f(x):

$f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}$

Read more on slope of a tangent here: brainly.com/question/26015157

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5 0

3 years ago

A jar contains 4 pennies, 5 nickels, and 2 dimes. Helpppp!!

coldgirl [10]

Answer:

A

Step-by-step explanation:

I may be wrong but 5/11 would be the 5 nickels out of the 11 coins so...

5 0

3 years ago

Read 2 more answers

Can someone please help

attashe74 [19]

Answer:

take 121 subtract it from 180 and you get 59 so angle d is 59°. and angle b is 154°

6 0

3 years ago

A rectangular poster is to contain 578 square inches of print. The margins at the top and bottom of the poster are to be 2 inche

lord [1]

Answer:

19 by 38

Step-by-step explanation:

The area of the poster, A=xy

Margin at both up and bottom is 2inches, at the right and left is 1 inch

Then we can say

(x-4)(y-2)= 578

Let us make y subject of the formula

(y-2)= 578/(x-4)

y=[ 578/(x-4)] + 2

If we substitute into the area A equation we have

A= x { [ 578/(x-4)] + 2}

A= 2x + (578x)/(x - 4)

If we differentiate we have

A'(x)= [2+578(x-4)+578x ]/ (x-4)^2

=[ 2(x-4)^2 + 578(x -4) + 578x ] / (x-4)^2

=[ 2(x^2 - 8x +16) + 578(x-4) + 578x ] /(x-4)^2

If we simplify this we have

=[ 2x^2 -16x +32+578x -578x - 2312]/ (x-4)^2

=( 2x^2 -16x - 2312) / (x-4)^2

At A'(x)= 0

= ( x^2 - 8x - 2312) / (x-4)^ =0

If we divide through by 2 we have

x^2 - 8x - 1156= 0

Solving the quadratic eqn( CHECK THE ATTACHMENT)

X= 38 or -30 then we choose the positive one, then x= 38

Then from area of the poster

A= (x-4)(y-2)= 578

Substitute 38 as value of x

(38-4)(y-2)= 578

34(y-2)=578

34y-68=578

34y=646

y=19

Hence dimensions of the poster is 19 by 38

CHECK THE ATTACHMENT FOR QUADRATIC SOLUTION

7 0

3 years ago