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tester [92]
3 years ago
5

ou need to implement a wireless network link between two buildings on a college campus. A wired network has already been impleme

nted within each building. The buildings are 100 meters apart. Which type of wireless antenna should you use on each side of the link
Computers and Technology
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

High-gain and directional wireless antenna.

Explanation:

WiFi can be defined as a wireless local area network that allows network devices such as access points (APs), computers (both laptops and desktops), smartphones, smart televisions, etc., to communicate with each other wirelessly over a short-ranged network. It is a standard communication network that uses radio waves to establish a channel (medium) between multiple network devices.

This ultimately implies that, the network range or distance covered by WiFi is largely dependent on transmission power and frequency. Generally, the standard range or distance covered by WiFi is about 50 meters (160 feet).

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver through the use of an antenna.

In this scenario, you need to implement a wireless network link between two buildings on a college campus, which are 100 meters apart.

A high-gain antenna is an electromagnetic device that typically has a gain rating of 12dBi or sometimes higher. Also, a highly directional antenna can only receive radio signals from a specific direction and it compresses the radio waves that are being transmitted from a sender in to a very narrow beam.

Hence, the two (2) type of wireless antenna you should use on each side of the link are a high-gain antenna and a directional wireless antenna.

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Define a method calcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a d
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import java.io.*;

public class Main {

   public static void main(String[] args) throws IOException {

       double baseLength = 0, baseWidth = 0, pyramidHeight = 0;

       Object[] volume;

       volume = calcPyramidVolume(baseLength, baseWidth, pyramidHeight);

   }

   public static Object[] calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight) {

       double area = calcBaseArea(baseLength, baseWidth);

       double volume = baseLength * baseWidth * pyramidHeight;

       return new Object[]{volume, area};

   }

   public static double calcBaseArea(double length, double width) {

       return length * width;

   }

}

Explanation:

The problem is flawed because it is completely inefficient for one to create two separate methods to calculate the volume and the area when they can be done at once.

The second problem is that it was never specified whether to return something from the calcBaseArea method.

I assumed it required it, so it is not advisable to initiate the method as a double, but rather create it as an Object so that it can return two values: the volume and the area.

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