Please help me with this question ☝️☝️
1 answer:
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Answer:
The area of the two-dimensional cross section is
Step-by-step explanation:
we know that
The two-dimensional cross section that is parallel to face ABC is a triangle congruent with the triangle ABC
Therefore
Calculate the area of triangle ABC
we have that
Triangles ABC and DEF are congruent
so
substitute
Hi there!
Combining th' like terms of the expressions.
(7y² - 3y) + (8y² - 8y)
7y² - 3y + 8y² - 8y
(7y² + 8y²) + (-3y - 8y)
15y² - 11y
Hence,
Option [ 1. ] - 15y² - 11y is Correct
~ Hope it helps!
Combining th' like terms of the expressions.
(7y² - 3y) + (8y² - 8y)
7y² - 3y + 8y² - 8y
(7y² + 8y²) + (-3y - 8y)
15y² - 11y
Hence,
Option [ 1. ] - 15y² - 11y is Correct
~ Hope it helps!