Answer:
Angle parking is more common than perpendicular parking.
Angle parking spots have half the blind spot as compared to perpendicular parking spaces
Step-by-step explanation:
Considering the available options, the true statement about angle parking is that" Angle parking is more common than perpendicular parking." Angle parking is mostly constructed and used for public parking. It is mostly used where the parking lots are quite busy such as motels or public garages.
Therefore, in this case, the answer is that "Angle parking is more common than perpendicular parking."
Also, "Angle parking spots have half the blind spot as compared to perpendicular parking spaces."
Answer:
1.626 and then theres a lot more numbers
Step-by-step explanation:
Answer:
b + g = 25
b = g + 3
Step-by-step explanation:
Let b = number of boys.
Let g = number of girls.
"Mrs. Smith has a total of 25 kids in her class."
b + g = 25
"There are 3 more boys than there are girls."
b = g + 3
The system of equations is:
b + g = 25
b = g + 3
Answer:
g ≥ -4
Step-by-step explanation:
3 ≤ 7 + g
3 - 7 ≤ 7 - 7 + g
-4 ≤ g
g ≥ -4
Answer:
Step-by-step explanation:
Let 
Subbing in:

a = 9, b = -2, c = -7
The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

Group together in groups of 2:

Now factor out what's common within each set of parenthesis:

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

Remember that 
so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring
gives us that x = 1 and -1. The other set is a bit more tricky. If
then
and

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:
±
which will simplify down to
±
Those are the 4 solutions to the quartic equation.