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zlopas [31]
3 years ago
7

Please help me with this question ☝️☝️

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

\frac{-4}{5}

Step-by-step explanation:

\frac{-4}{15}* 3 = -4/5

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Which of the following are true statements about angle parking. Angle parking spots have a larger blind spaces than perpendicula
S_A_V [24]

Answer:

Angle parking is more common than perpendicular parking.

Angle parking spots have half the blind spot as compared to perpendicular parking spaces

Step-by-step explanation:

Considering the available options, the true statement about angle parking is that" Angle parking is more common than perpendicular parking." Angle parking is mostly constructed and used for public parking. It is mostly used where the parking lots are quite busy such as motels or public garages.

Therefore, in this case, the answer is that "Angle parking is more common than perpendicular parking."

Also, "Angle parking spots have half the blind spot as compared to perpendicular parking spaces."

5 0
2 years ago
Please help 7/9 x 7/9 x 7/9 x 7/9 x 7/9 x 7/9 x 7/9 x 7/9 =
mixas84 [53]

Answer:

1.626 and then theres a lot more numbers

Step-by-step explanation:

6 0
3 years ago
Mrs. Smith has a total of 25 kids in her class. There are 3 more boys than there are girls. Write a system of equations to model
Svetlanka [38]

Answer:

b + g = 25

b = g + 3

Step-by-step explanation:

Let b = number of boys.

Let g = number of girls.

"Mrs. Smith has a total of 25 kids in her class."

b + g = 25

"There are 3 more boys than there are girls."

b = g + 3

The system of equations is:

b + g = 25

b = g + 3

6 0
3 years ago
Solve the equality, pls help with this
labwork [276]

Answer:

g ≥ -4

Step-by-step explanation:

3 ≤ 7 + g

3 - 7 ≤ 7 - 7 + g

-4 ≤ g

g ≥ -4

4 0
3 years ago
What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

5 0
3 years ago
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