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AysviL [449]
3 years ago
12

If 6 pencils cost $3.60 what is the unit price of the pencils

Mathematics
1 answer:
Natali [406]3 years ago
4 0
Your answer is 21.6

Step by Step:

-put it like a regular multiplication problem
-For the 6 add a decimal and then two 0s
-make sure your decimals lines up together
-once you get your answer you notice 3.60 has one number.(Leave the zero out) ^
- that’s how many times you move to put your decimal in the right place
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F(x)=x^2-2x-3<br><br><br><br><br><br> (so I need the done in like 20 min)
maks197457 [2]

Vertex point: (1, -4)

X-intercepts: (-1, 0) , (3, 0)

Y-intercept: (0, -3)

Axis of symmetry: x = 1

This function will create a parabola that opens upwards. I’m not entirely sure what I was supposed to answer. Hopefully this covered it. I’ll attach an image of the parabola in case I missed anything.

7 0
3 years ago
PLEASE I REALLY NEED HELP!
vagabundo [1.1K]

Answer:

\frac{3}{28}

Step-by-step explanation:

Probability (P) is calculated as

P = \frac{requiredoutcome}{count}

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = \frac{3}{8}

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = \frac{2}{7}

P( red and red ) = \frac{3}{8}  × \frac{2}{7} = \frac{6}{56} = \frac{3}{28}

6 0
3 years ago
What is the distance between the points (-1,-9) and (4,-2)?
Crank

\sqrt{74}, or 8.60

Just use the distance formula

4 0
3 years ago
Solve for x. -1/3(4x+2)=1/3(x+11)
sineoko [7]

Answer:

X= -13/5

Step-by-step explanation:

i hope this helps :)

6 0
2 years ago
Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity
Anna11 [10]

Answer:

5

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is \frac{LT^{-2}}{LT^{-1}}

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0
3 years ago
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