All categories

3 years ago

Number 3. What is the value of x?

Mathematics

1 answer:

kodGreya [7K]3 years ago

7 0

Answer:

the value of x would be 7

Step-by-step explanation:

because im smartttt

You might be interested in

What is the product of (-6)(-7)(-1)?<br> оооо

Yanka [14]

Answer:

-42

Explanation:

(-6)(-7)(-1)

do (-6)(-7)

-negative sign and -negative sign= +positive sign

(-6)(-7)=42

(42)(-1)

+positive sign and -negative sign=-negative sign

answer:

-42

3 0

3 years ago

Read 2 more answers

A cab company charges $1 fee for the cab ride,

sweet-ann [11.9K]

Answer:

12 miles

Step-by-step explanation:

25 - $1 fee= 24/$2 per mile = 12 miles

7 0

3 years ago

Read 2 more answers

The sum of three consecutive even numbers is one hundred sixty-two. What is the smallest of the three numbers?

zepelin [54]

Since the numbers are consecutive, they must be near each other in size, and therefore near one-third of 168. And since the lower number is -2 off the middle, and the upper number is +2 from the middle, the middle number must be exactly one-third of 168—otherwise the sum of the three could never be 168. Labelling the three consecutive numbers as x, y, and z:

x + y + z = 168

(y-2) + y + (y+2) = 168.

3y = 168

y = 56

therefore the smallest number (x) = 54.
436 viewsView upvotes

1

Related Questions (More Answers Below)

3 0

3 years ago

Read 2 more answers

Please help on the answer with explanation! picture provided

Alisiya [41]

Answer:

Step-by-step explanation:

3 0

3 years ago

Quadrilateral A’B’C’D’ is a dilation of quadrilateral ABCD about point P. Quadrilateral ABCD is shown. Side AB is labeled 5. Sid

Stolb23 [73]

Answer: The correct option is (A) reduction.

Step-by-step explanation: Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.

As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:

AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.

And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:

$A'B'=1\dfrac{1}{4}=\dfrac{5}{4}~\textup{units},~~B'C'=1~\textup{units},~~C'D'=2\dfrac{1}{2}=\dfrac{5}{2}~\textup{units},\\\\D'A'=1\dfrac{1}{2}=\dfrac{3}{2}~\textup{units}.$

We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.

Now, the scale factor is given by

$S=\dfrac{\textup{length of a side of the dilated figure}}{\textup{length of the corresponding side of the original figure}}\\\\\\\Rightarrow S=\dfrac{A'B'}{AB}=\dfrac{\frac{5}{4}}{5}=\dfrac{5}{4\times5}=\dfrac{1}{4}$

Since the scale factor is less than 1, so the dilation will be a reduction.

5 0

3 years ago

Read 2 more answers