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lesya692 [45]
3 years ago
11

How to solve for y??????

Mathematics
1 answer:
tia_tia [17]3 years ago
8 0
What he said above yeah y
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8. A model airplane is shot into the air. Its path is approximated by the
rjkz [21]

Here is another one of those " quadratic word problems " at hand, which is great!

By the function that is given to us ( which I believe is meant to be h(t) = - 5t^2 + 251 ) the airplane is launched at a height of 251 metres, with no velocity. Anyhow, we need to determine the duration with which the airplane will strike the ground, and to do so we can set up the following equation, - 5t^2 + 251 = 0 - solving for t, otherwise known to be the time!

See the procedure below -

-5t^2+251=0 - Subtract 251 from either side,

-5t^2=-251 - Divide either side by - 5,

t^2=\frac{251}{5} - And, now isolate t, receiving two solutions,

t=\sqrt{\frac{251}{5}},\:t=-\sqrt{\frac{251}{5}}

However, time can't be a negative value. Thus our solution is \sqrt{251 / 5}, which is ( about ) 7.085 seconds!

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3 years ago
Help me with this problem please #23
My name is Ann [436]
It takes 6 minutes for the printer to print 21 photos
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4 years ago
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Alekssandra [29.7K]

Answer:

80

Step-by-step explanation:

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I didn't understand that fraction part of the question. Sorry.

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3 years ago
(3^2+4−2)(2^2−3−4) can you guys please solve this for me please.
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Answer:

-33

Step-by-step explanation:

(3^2+4-2)(2^2-3-4)

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(11) · (-3)

(-33)

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