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Leokris [45]
2 years ago
9

Help me. what is three and one half times one and two thirds

Mathematics
2 answers:
AlekseyPX2 years ago
8 0

Answer:

= 4 2/3

Step-by-step explanation:

make fractions like that into improper

7/2 * 4/3

tthen multiply tops and multiply bottomes, anfd then reduce

Natali [406]2 years ago
5 0

Answer:

3 1/2 × 1 2/3 = 5 5/6.

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What is the range of the graphed function?
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Step-by-step explanation:

The range is all the y's that an equation can produce or all the y's on a graph of the function.

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Which expression is equivalent to the given expression? 17x−32x
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3 years ago
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3 years ago
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Suppose that theta is an angle in standard position whose terminal side Intersects the unit circle at (-11/61, -60/61)
Blizzard [7]

Answer:

The exact values of the tangent, secant and cosine of angle theta are, respectively:

\cos \theta = -\frac{11}{61}

\tan \theta = \frac{-\frac{60}{61} }{-\frac{11}{61} } = \frac{60}{11}

\sec \theta = \frac{1}{-\frac{11}{61} } = -\frac{61}{11}

Step-by-step explanation:

The components of the unit vector are x = -\frac{11}{61} and y = -\frac{60}{61}. Since r = 1, then x = \cos \theta and y = \sin \theta. By Trigonometry, tangent and secant can be calculated by the following expressions:

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}

\sec \theta = \frac{1}{\cos \theta} = \frac{1}{x}

Now, the exact values of the tangent, secant and cosine of angle theta are, respectively:

\cos \theta = -\frac{11}{61}

\tan \theta = \frac{-\frac{60}{61} }{-\frac{11}{61} } = \frac{60}{11}

\sec \theta = \frac{1}{-\frac{11}{61} } = -\frac{61}{11}

3 0
3 years ago
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