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3 years ago

How to use base ten blocks to divide

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

You have to put them into a group and then divide them

Sedbober [7]3 years ago

6 0

Its very easy. Whats the math problem ill help you out.

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The graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k: a parabola with a vertex of 4, negative 2 What is the

4vir4ik [10]

we know that

The vertex of the function $f(x)=x^{2}$ is the point $(0,0)$

The vertex of the function $f(x)=(x-h)^{2}+k$ is the point $(4,-2)$

The x-coordinate of the vertex is equal to h

the y-coordinate of the vertex is equal to k

the value of h is $4$

the value of k is $-2$

the equation is

$f(x)=(x-4)^{2}-2$

therefore

<u>the answer is the option a</u>

$4$

4 0

3 years ago

Read 2 more answers

HAVE AN AMAZING DAY <br> WILL GIVE BRAINLST

VikaD [51]

Answer:

thx.......... can i get brainliest

4 0

3 years ago

Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f

BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = $\frac{width}{2}$

ME = $\frac{0.14}{2}$

ME = $0.07$

$ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}$

use p = 0.5

z at 95.8% is 1.727(using calculator)

$0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}$

$\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}$

$(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}$

$n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}$

$n \geq 152.169$

So, Option B is true

Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

6 0

3 years ago

Plz help!!!!!!!!!!!!!

vaieri [72.5K]

Answer: The correct answer is -2,5/2 which is the last answer.

Step-by-step explanation:

* Hopefully the work below helps:)Mark me the brainliest:)!!

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3 years ago

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Math item stem image<br> does this figure have symmetry

bearhunter [10]

Answer: yes

Step-by-step explanation:

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3 years ago