Answer:
B
Step-by-step explanation:
sin(theta) = sqrt(1-cos^2(theta)
sin(theta)=sqrt(1-1/2)=sqrt(1/2)=sqrt(2)/2 but as theta is in IV quadrant, sin(theta) will be negative
q = 6; r = 7
Undefined
If the slope was a horizontal line, then we could say y=2, however, it is only going through the x-axis so it would be x=2, but in terms of y it is undefined.
The area of a rectangle:
×
× ×
-Result:
Over which interval(s) is the function decreasing?
