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Travka [436]
3 years ago
10

Whats 3.2r + 14.7=6.74

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0

Answer:


Step-by-step explanation:

Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 14.7 from both sides

3.2r + 14.7 (-14.7) = 6.74 (-14.7)

3.2r = 6.74 - 14.7

3.2r = -7.96

Isolate the r. Divide 3.2 from both sides

(3.2r)/3.2 = (-7.96)/3.2

r = -7.96/3.2

r = -2.4875

-2.4875 is your answer

~

Nata [24]3 years ago
6 0

<u><em>r=-199/80 is the right answer.</em></u> First, you had to multiply by 100 from both sides of the equation. And it gave us, 3.2r*100+14.7*100=6.74*100. Next, you had to refine, and it gave us, 320r+1470=674. Then, subtract by 1470 from both sides of equation. And it gave us, 320r+1470-1470=674-1470. Simplify, and it gave us, 320r=-796. You can also divide by 320 from both sides of equation. And it gave us, \frac{320r}{320}=\frac{-796}{320}. And finally, simplify, and it gave us the answer is <em><u>r=-199/80 is the right answer.</u></em> Hope this helps! And thank you for posting your question at here on brainly. And have a great day! -Charlie

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No idea what the previous part of the problem is, but you have

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f(x)=\displaystyle8\sum_{n\ge0}\left(-\dfrac14\right)^nx^{2n}

which is valid for \left|-\dfrac{x^2}4\right|, or |x|. So the integral from 0 to 2 is

\displaystyle\int_0^2f(x)\,\mathrm dx=\int_0^28\sum_{n\ge0}\left(-\frac14\right)^nx^{2n}\,\mathrm dx
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Note that since the power series only converges on the interval if x is strictly less than 2, which means we have to treat this as an improper integral.

=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\int_0^tx^{2n}\,\mathrm dx[/tex]
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6 0
3 years ago
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marshall27 [118]

Answer:

\boxed{x = p(m - n)}

Step-by-step explanation:

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aleksklad [387]

Answer:

116

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A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus ​, which is 46feet above the vertex of th
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the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

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2

=a

2

+b

2

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

2

=(18)

2

+b

2

,

b

2

=400−324=76

.

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

b

2

y

2

−

a

2

x

2

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

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y

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−

324

x

2

=1 .

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3 years ago
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