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2 years ago

Whats 3.2r + 14.7=6.74

Mathematics

2 answers:

DIA [1.3K]2 years ago

7 0

Answer:

Step-by-step explanation:

Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 14.7 from both sides

3.2r + 14.7 (-14.7) = 6.74 (-14.7)

3.2r = 6.74 - 14.7

3.2r = -7.96

Isolate the r. Divide 3.2 from both sides

(3.2r)/3.2 = (-7.96)/3.2

r = -7.96/3.2

r = -2.4875

-2.4875 is your answer

Nata [24]2 years ago

6 0

r=-199/80 is the right answer. First, you had to multiply by 100 from both sides of the equation. And it gave us, $3.2r*100+14.7*100=6.74*100$ . Next, you had to refine, and it gave us, $320r+1470=674$ . Then, subtract by 1470 from both sides of equation. And it gave us, $320r+1470-1470=674-1470$ . Simplify, and it gave us, $320r=-796$ . You can also divide by 320 from both sides of equation. And it gave us, $\frac{320r}{320}=\frac{-796}{320}$ . And finally, simplify, and it gave us the answer is r=-199/80 is the right answer. Hope this helps! And thank you for posting your question at here on brainly. And have a great day! -Charlie

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Answer:

k = 10

Step-by-step explanation:

Difference means subtract.

2k - 8 = 12

is how that statement is translated.

Add 8 to both sides.

2k - 8 + 8 = 12 + 8

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Divide by 2

2k/2 = 20/2

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So the correct answer is:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Previous concepts

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Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

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