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Natalka [10]
3 years ago
5

4. Which should be done after a volcanic eruption?

Chemistry
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

4. D sounds like the best option.

5. D is the correct answer.

Explanation:

You're Welcome

You might be interested in
How long will it take to deposit 6.32 g of copper from a CuSO4(aq) solution using a current of 0.554 amps
rjkz [21]

Answer:

34672.96 s

Explanation:

m = Mass of copper = 6.32 g

M = Molar mass of copper = 63.5 g/mol

F = Faraday constant = 96500 C/mol

The electrode equation would be

Cu^{2+}(aq)+2e^{-}=Cu(s)

Number of electrons = 2 = e

I = Current = 0.554 A

t = Time taken

Charge would be

Q=\dfrac{m}{M}eF\\\RightarrowQ=\dfrac{6.32}{63.5}\times 2\times 96500\\\Rightarrow Q=19208.82\ \text{C}

Charge is given by

Q=It\\\Rightarrow t=\dfrac{Q}{I}\\\Rightarrow t=\dfrac{19208.82}{0.554}\\\Rightarrow t=34672.96\ \text{s}

Time taken to deposit the copper is 34672.96 s.

8 0
3 years ago
Which nuclides are used to date the remains of a once-living organism?
VashaNatasha [74]
The  answer is (1) C-14 and C-12. The life on the earth is carbon based. Carbon is important in living organisms. So C-14 and C-12 can be used to date the remains of a once-living organism. 
8 0
3 years ago
Show the calculation of the energy involved in condensation of 150 grams of steam at 100oC if the Heat of Vaporization for water
vaieri [72.5K]

Answer : The energy involved in condensation is, 339 kJ

Explanation :

Formula used :

q=m\times L

where,

q = heat required = ?

L = latent heat of vaporization of water = 2.26kJ/g

m = mass of water = 150 g

Now put all the given values in the above formula, we get:

q=(150g)\times (2.26kJ/g)

q=339kJ

Therefore, the energy involved in condensation is, 339 kJ

4 0
3 years ago
The law of conservation of energy states that if the system gains heat the surroundings ________?
Arlecino [84]
The surroundings would lose heat.
8 0
3 years ago
The vapor pressure of pure water at 250C is 23.77 torr. What is the vapor pressure of water above a solution that is 1.500 m glu
Olegator [25]

Answer:

Vapor pressure of water = 23.14torr

Explanation:

When you made a solution, vapor pressure decreases following Raoult's law:

P_{solution} = X_{solvent} P_{solvent}

<em>Where P is vapor pressure and X mole fraction</em>

As vapor pressure of water is 23.77torr we must find the mole fraction of water knowing the solution is 1.500m glucose (That is 1.500 moles of glucose per kg of water = 1000g of water).

1000g of H₂O are, in moles (Molar mass: 18.02g/mol):

1000g H₂O ₓ (1mole / 18.02g) = 55.5 moles of H₂O.

As we know now the solution contains 55.5 moles of water and 1.5 moles of glucose. Thus, mole fraction of water (Solvent) is:

X_{H_2O} = \frac{55.5molesH_2O}{55.5molesH_2O + 1.5 molesGlucose} = 0.9737

Replacing in Raoult's law, pressure of water above the solution is:

P_{solution} = X_{solvent} P_{solvent}

P_{solution} = 0.9737*23.77torr

<h3>Vapor pressure of water = 23.14torr</h3>
7 0
3 years ago
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