Answer:
W=5
Step-by-step explanation:
W=Width=Length + 1
L = Length
Area = Length * Width = 20
Area = L * W = L * (L+1) = 20
Distribute the L: L^2 + L = 20
Subtract 20 from both sides: L^2 + L -20 = 20-20
Simplify: L^2+L-20=0
Factor (L-4)(L+5)=0
Solve using the zero property: L-4=0, L=4 L+5=0, L=-5
The two options for length are 4 and -5. Only 4 will work for L since it cannot be negative. Width is Length + 1 = 5
Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
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<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer:
F^-1 (x) = 3x/2+5/4
Step-by-step explanation:
First, replace f(x) with y
Replace every x with a y and replace every y with an x .
Solve the equation from Step 2 for y
Replace y with f−1(x) f − 1 ( x )
Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.
Hope this helps! Stay Safe!