Answer:
<em>The graph of </em>y + 1 = −3/5 (x − 4)<em> would be a straight line. The graph figure is attached below.</em>
Step-by-step explanation:
As the linear equation y + 1 = −3/5 (x − 4) is given.
Since y-y₁ = m (x - x₁) is the Point-slope form is the general form y-y₁=m(x-x₁) for linear equations.
Hence, from the linear equation we can determine the slop which is m = -3/5
Also, when we put x = 0 in the linear equation, we determine the y-intercept as follows:
y + 1 = −3/5 (x − 4)
y + 1 = -3/5(-4) ∵x = 0
y = 12/5 - 1
y = 7/5
y-intercept: 7/5
Hence,
Table for some points can be made for x and values as:
<h3><em>x y</em></h3>
0<em> </em><em> 7/5</em>
<em>1 4/5</em>
<em />
<em>The graph of </em>y + 1 = −3/5 (x − 4)<em> would be a straight line. The graph figure is attached below.</em>
<em />
<em>Keywords: graph, straight line</em>
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Answer:
B) 2a√15a
Step-by-step explanation:
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers. 2a√15a
Answer:
c b a
Step-by-step explanation:
Answer:

Step-by-step explanation:
1.235
= 1 + 0.235 ( the place value of the 5 is thousandths ) , then
=
+ 
=
( divide numerator/denominator by 5 )
=
← in simplest form
If the discriminant is positive,that means that there are roots that are real and therefore, when y=0, the roots are there and for the quadratic to meet it has to go down (or up if in ax²+bx+c a is negative). If the discriminant is 0, that means that since the x value of the vertex is -b/2a and if you have
x=

and b^2-4ac=0, we're left with 0 and we are therefore left with -b/2a as the vertex and the vertex being the x intercept. If the discriminant is negative, that means that there is no y intercept and the vertex therefore has to be over y=0