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3 years ago

Which of the following is not a promotional tactic used by a seller?

Mathematics

2 answers:

Leviafan [203]3 years ago

6 0

Answer:

we conclude that the 'bait and switch' technique is not a promotional tactic used by a seller.

Hence, 'a' is the correct option.

Step-by-step explanation:

From the given options, the 'bait and switch' technique is not a promotional tactic used by a seller.

'Bait and switch' is a deceptive sale practice using which the sells try to attract (bait) the customers by offering attractive prices on certain items, but when the customers tend to go to the shop to buy the items, they witness the unavailability of the goods, or find the prices go higher compared to what they had been offered.

Now, since the customers are already present at the shop, the sellers try to pressurize the customer so that they could buy something else.

Therefore, we conclude that the 'bait and switch' technique is not a promotional tactic used by a seller.

Hence, 'a' is the correct option.

pychu [463]3 years ago

4 0

Answer:

Step-by-step explanation:

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If 1 kg of milk had 0.264 kg of fat, then find the amount fat in 12.5 kg of milk.<br>

beks73 [17]

1 kg--> 0.264 kg fat

:. 12.5 kg--> (0.264*12.5) 3.3 kg fat

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3 years ago

A pizza has 8 slices and papa gino's sells the whole pizza for $16. What is the unit rate for a slice of pizza?

BabaBlast [244]

Answer:

It would be $2 per piece, because 16 divided by 8 is two.

Step-by-step explanation:

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3 years ago

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Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

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3 years ago

Alana biked 15 miles in 1 hour. How many miles did she bike in 3 hours?

Law Incorporation [45]

Alana biked 45 minutes in 3 hours.

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3 years ago

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Find the length of a diagonal of a rectangular box of length 12 cm, width 5 cm and height 4 cm.

Nezavi [6.7K]

Answer:13

Step-by-step explanation:

this is an phythagoras question

12 x 12 = 144

5 x 5 = 25

144 + 25 = 169

$\sqrt{169$

=13

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2 years ago

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