![\bf \begin{array}{ccccllll} &distance&rate&time(hrs)\\ &\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\ \textit{first car}&d&40&t\\ \textit{second car}&d&60&t+2 \end{array} \\ \quad \\\\\\ d=d\implies (40)(t)=(60)(t+2)](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccllll%7D%0A%26distance%26rate%26time%28hrs%29%5C%5C%0A%26%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%26%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%26%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5C%5C%0A%5Ctextit%7Bfirst%20car%7D%26d%2640%26t%5C%5C%0A%5Ctextit%7Bsecond%20car%7D%26d%2660%26t%2B2%0A%5Cend%7Barray%7D%0A%5C%5C%20%5Cquad%20%5C%5C%5C%5C%5C%5C%0Ad%3Dd%5Cimplies%20%2840%29%28t%29%3D%2860%29%28t%2B2%29)
"t", is the time the first car has travelled when reaching "d" distance,
whatever that is, at that point, the second car is passing it
Answer:
-200
Step-by-step explanation:
(happy to help)
The answer would be A. I did the math and got -168.
Answer: 57.5
Step-by-step explanation: The first thing you need to know about the order of operations is that multiplication and division come before addition and subtraction.
So in this problem, we are going to divide before we add.
Since 30 divided by 4 is 7.5, our next step will read 50 + 7.5 and 50 + 7.5 simplifies to 14.