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3 years ago

There are 800 students at O'Farrell. 40% of the students chose hybrid learning. How many

Mathematics

1 answer:

Ghella [55]3 years ago

3 0

Answer:

840

Step-by-step explanation:

800+40=840

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Which expression represents 6 more then x

notka56 [123]

X+6 of that is one of the answer options

8 0

3 years ago

Can someone please explain expanded form with this number 15,409

Anarel [89]

The expanded form of 15,409 would be 15,000 + 400 + 9.

Your 15 would alone be 15,000. The 409 is turned into zeros.
For 409, take the 9 off of the end and keep it by itself, and then add a zero in replace for the 9, which makes 400.
The 9 should come in at the last part as it is the last number.

Add them all together and you should get <span>15,000 + 400 + 9.</span>

3 0

3 years ago

A number, n, is multiplied by - 5/8. The products is - 0.40 What is the value of n? It would also help if you would explain how

Kay [80]

I'm not sure if those numbers are negatives or thats just a hyphen but:

N(-5/8)=-0.40

Division is always the opposite of multiplication

-0.40/(-5/8)=0.64

N=0.64

5 0

2 years ago

Which value from the set (5,7,9,11,13) make inequality w-4<8 true?

ira [324]

Answer:

5,7,9,11

Step-by-step explanation:

8 0

3 years ago

Ronald Dairo is helping the local indus-

nadya68 [22]

Answer:

Mr. Dairo can produce 20580 pieces of Papaya rosette in two weeks.

Step-by-step explanation:

Papaya rosette pieces on first day = 5890

Papaya rosette Pieces on second day = 7020

Papaya rosette Pieces of third day = 8150

Let

$a_1 = 5890\\a_2 = 7020\\a_3 = 8150$

We can check if these numbers are part of a sequence.

In order to check, common difference will be found first.

$d = a_2-a_1 = 7020-5890 = 1130\\d =a_3-a_2 = 8150-7020 = 1130$

It can be observed that the common difference is same. When the common difference is same, the sequence is said to be an arithmetic sequence.

The formula for arithmetic sequence is given by:

$a_n = a_1+(n-1)d$

Putting the values

$a_n = 5890+(n-1)(1130)\\a_n = 5890+1130n-1130\\a_n =4760+1130n$

The formula for nth term can be used to find any term. As we have to find the number of papaya rosette pieces after two weeks which means that we need to find the number of pieces on 14th day.

So,

$a_{14}= 4760+1130(14)\\a_{14} = 4760+15820\\a_{14} = 20580$

Hence,

Mr. Dairo can produce 20580 pieces of Papaya rosette in two weeks.

5 0

2 years ago