cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
Answer:
£100.32
Step-by-step explanation:
→ In order to work out the multiplier from a increase, you have to add 100 to the percentage and then divide by 100 so,
14 + 100 = 114
114 ÷ 100 = 1.14
→ This means the decimal multiplier is 1.14, now all we do is multiply the multiplier by the cost
£88 × 1.14 = £100.32
9514 1404 393
Answer:
y = -3x
Step-by-step explanation:
The slope formula gives the slope of the segment between the given points.
m = (y2 -y1)/(x2 -x1)
m = (-3 -(-5))/(2 -(-4)) = 2/6 = 1/3
The slope of the perpendicular line is the opposite reciprocal of this, so is ...
m' = -1/(1/3) = -3
A perpendicular line is ...
y = -3x
Therefore the point P is at 3.46 cm from O and it lies on the angle bisector of ∠XOY
<h3>What is an Angle Bisector ?</h3>
The ray that bisects the angle into half is called Angle Bisector.
It is given that ∠XOY = 60 degree
the length of OX = 4.5 cm
OY =5 cm
The point M is on OX such that
OM = 2 MX
so The M is at 3 cm from O
The point P lies in the acute angle such that the distance between point P and OX and OY is always same and at 3 cm from M
According to the angle bisector theorem converse states that if a point is in the interior of an angle and is at equal distance from the sides then it lies on the bisector of that angle.
As it can be seen from the image that a point equidistant from the rays , at 3 cm from M will be at
By Pythagoras Theorem
3² +3² = OP²
OP = 2
= 3.46 cm from O
To know more about Angle Bisector
brainly.com/question/12896755
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Answer:
A
Step-by-step explanation:
A