2f(2Answer:
Step-by-step explanation:
f(1)=8
f(2)= 2(8) = 16
f(3) = 2(16) = 32
f(4) = 2(32) = 64
f(5) = 2(64) =128
Answer:
2t-7
Step-by-step explanation:
2(t-4)+1
When you multiply out the two, you get:
2(t) - 2(4) +1
2t - 8 + 1
2t-7
A graph shows the function can be factored as
f(x) = (x -1)((x-8)² +1)
There is one real root and there are two complex roots. The latter can be found from the vertex form factor:
(x - 8)² + 1 = 0
(x - 8)² = -1
x - 8 = ±√(-1) = ±i
x = 8 ± i
The zeros of the function are {1, 8-i, 8+i}.
Answer:
rhombus
Step-by-step explanation:
lol