Solve this quadratic equation using the quadratic formula.<br> (3 - y)(y + 4) = 3y

Match the word with the definition.

Goryan [66]

Step-by-step explanation:

practical range = 8

vertical line test = 5

range = 3

domain = 2

relation = 1

function = 4

function Notation =6

practical domain=7

5 0

2 years ago

PLS NEED HELP!!!!!!!!!!!

ivolga24 [154]

Answer: Uhh

Step-by-step explanation:

5 0

2 years ago

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A surveyor leave her base camp and drive 42 km on a bearing of 032, she then drive 28km on a bearing of 154.How far is she then

aleksklad [387]

Answer:

Step-by-step explanation:

The scenario is represented in the attached photo. Triangle ABC is formed. AB represents her distance from her base camp. We would determine BC by applying the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and B is the angle corresponding to b. It becomes

AB² = AC² + BC² - 2(AC × BC)CosC

AB² = 42² + 28² - 2(42 × 28)Cos58

AB² = 1764 + 784 - 2(1176Cos58)

AB² = 2548 - 1246.37 = 1301.63

AB = √1301.63

AB = 36.08 km

To find the bearing, we would determine angle B by applying sine rule

AB/SinC = AC/SinB

36.08/Sin58 = 42/SinB

Cross multiplying, it becomes

36.08SinB = 42Sin58

SinB = 42Sin58/36.08 = 0.987

B = Sin^-1(0.987)

B = 81°

Therefore, her bearing from the base camp is

360 - 81 = 279°

8 0

2 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

2 years ago

A bug starts at the origin of the coordinate plane. The bug moves 1/4 units right and 1/4 units down to point A. Which graph sho

Vsevolod [243]

Answer:

<h2>The Answer would be (0.25, -0.25)</h2>

Step-by-step explanation:

Since you started at the origin of the plane, it would be obvious that your place would be 0.25 on the x-axis. The template for this would be (x,y) x- right and left. y- up and down. On the y-axis, the bug moved 0.25 DOWN to point A. That would be a negative since on the y-axis, it counts up to positives and down to negative. Similar to the x-axis, it counts right to positives, left to negatives. Hope this helped!

3 0

3 years ago

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Solve this quadratic equation using the quadratic formula. (3 - y)(y + 4) = 3y - 5