Answer:
The dimension of this rectangle = 2mm by 21mm
Where 2 mm = Width of the rectangle
21 mm = Length of the rectangle.
Step-by-step explanation:
The formula for the perimeter of a rectangle = 2(L + W)
= 2L + 2W
The perimeter = 46 mm
L = 3x + 3
W = x - 4
P = 2L + 2W
46mm = 2(3x + 3) + 2(x - 4)
46 = 6x + 6 + 2x - 8
Collect like terms
46 +8 -6 = 6x + 2x
48 = 8x
x = 48/8
x = 6
Since the Length = 3x + 3
= 3(6) + 3
= 18 + 3
= 21mm
Since the Width = x - 4
= 6 - 4
= 2mm
Therefore, the dimension of this rectangle = 2mm by 21mm
Where 2 mm = Width of the rectangle
21 mm = Length of the rectangle.
Step-by-step explanation:
log2x = 1 - log(x+4)
log2x = log10 - log(x+4)
log2x = log[10/(x+4)]
2x = 10/(x+4)
2x(x+4) = 10
2x² + 8x - 10 = 0
÷2 both sides of equation
x² + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5, 1
x isn't be -5 because logA, A need to be > 0
So, x value is 1
1.30 :)
All you have to do is see if the number on your left is greater than 5 or not if it’s is round up 1 if not it stays the same !
Hope this helped !!!
Length(l)= 2w
width(w)= w
Perimeter(P)= 2w+2l= 72 (simplify expression: divide each side by 2 )
P= w+l= 36 (plug in "2w" for "l")
P= w+(2w)= 36
P= 3w= 36 (divide each side by 3 to find the width)
w= 12 units
find length:
l=2w
l= 2(12)
l= 24 units
Answer:
The length of this rectangle is 24 units and the width is 12 units.
