The points with coordinates (x, y) that are on the line of the equation of the line relationship between the side of a square, x and the perimeter, y include;

(1, 4), (2, 8), (3, 12) ....(n, 4·n).

Where n is a positive number.

Step-by-step explanation:

The formula to determine the length of the perimeter of a square is,

Length of the perimeter of a square = Length of a side of the square multiplied by 4.

That is Perimeter of square = Side of square × 4

The relationship between the length of one side of a square and the perimeter of the square can be represented by the equation

y = 4×d which is a straight line with a slope of 4 passing through the origin

Points o the line include

(1, 4), (2, 8), (3, 12), etc.

The x and y coordinates take the form

(x, 4·x)

5 0

2 years ago

Claire paid $5.75 for a movie ticket. She wants to buy popcorn for $4.95 and a drink for $3.98. Claire brought $15 to the theate

Evgesh-ka [11]

The answer is C. hope this helped

4 0

3 years ago

Read 2 more answers

(a) What is wrong with the following equation? x2 + x − 42 x − 6 = x + 7 (x − 6)(x + 7) ≠ x2 + x − 42 The left-hand side is not

jeka94

Answer:

Attached please find answer

Step-by-step explanation:

= (x² + x - 42) / (x - 6)

= [x² + (7x - 6x) - 42] / (x - 6)

= [x² + 7x - 6x - 42] / (x - 6)

= [(x² + 7x) - (6x + 42)] / (x - 6)

= [x(x + 7) - 6(x + 7)] / (x - 6)

= [(x + 7)(x - 6)] / (x - 6)

= x + 7 → when x approches 6

= 6 + 7

= 13

Other method:

Lim (x² + x - 42) / (x - 6)

x→ 6

When x → 6, there is an indeterminate expression because: 6 - 6 = 0

Do you know the l'Hôpital's rule, when x → a:

Lim [ f(x) / g(x) ] = Lim [ f'(x) / g'(x) ]

f(x) = x² + x - 42

f'(x) = 2x + 1

g(x) = x - 6

g'(x) = 1

= f'(x) / g'(x)

= (2x + 1)/1

= 2x + 1 → when x approches 6

= 12 + 1

= 13

3 0

2 years ago